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Finding the Inverse Hyperbolic Sine of Complex Number in Golang

  • Last Updated : 01 Apr, 2020

Go language provides inbuilt support for basic constants and mathematical functions for complex numbers with the help of the cmplx package. You are allowed to find the inverse hyperbolic sine of the specified complex number with the help of Asinh() function provided by the math/cmplx package. So, you need to add a math/cmplx package in your program with the help of the import keyword to access the Asinh() function.

Syntax:

func Asinh(x complex128) complex128

Let us discuss this concept with the help of the given examples:

Example 1:




// Golang program to illustrate how to find the
// Inverse Hyperbolic Sine of Complex Number
package main
  
import (
    "fmt"
    "math/cmplx"
)
  
// Main function
func main() {
  
    // Finding inverse hyperbolic sine of
    // the specified complex number
    // Using Asinh() function
    res_1 := cmplx.Asinh(2 + 5i)
    res_2 := cmplx.Asinh(-9 + 8i)
    res_3 := cmplx.Asinh(-5 - 7i)
  
    // Displaying the result
    fmt.Println("Result 1:", res_1)
    fmt.Println("Result 2:", res_2)
    fmt.Println("Result 3:", res_3)
}

Output:

Result 1: (2.37054853731792+1.184231684275022i)
Result 2: (-3.1817205225071747+0.7249311476979132i)
Result 3: (-2.8440976626506607-0.9473406443130534i)

Example 2:




// Golang program to illustrate how to find
// Inverse Hyperbolic Sine of Complex Number
  
package main
  
import (
    "fmt"
    "math/cmplx"
)
  
// Main function
func main() {
  
    cnumber_1 := complex(2, 3)
    cnumber_2 := complex(6, 8)
  
    // Finding inverse hyperbolic sine
    cvalue_1 := cmplx.Asinh(cnumber_1)
    cvalue_2 := cmplx.Asinh(cnumber_2)
  
    // Sum of two inverse 
    // hyperbolic sine values
    res := cvalue_1 + cvalue_2
  
    // Displaying results
    fmt.Println("Complex Number 1: ", cnumber_1)
    fmt.Println("Inverse hyperbolic sine 1: ", cvalue_1)
  
    fmt.Println("Complex Number 2: ", cnumber_2)
    fmt.Println("Inverse hyperbolic sine 2: ", cvalue_2)
    fmt.Println("Sum of inverse hyperbolic sines : ", res)
  
}

Output:

Complex Number 1:  (2+3i)
Inverse hyperbolic sine 1:  (1.9686379257930964+0.9646585044076027i)
Complex Number 2:  (6+8i)
Inverse hyperbolic sine 2:  (2.995040217583994+0.9248902126310973i)
Sum of inverse hyperbolic sines :  (4.9636781433770905+1.8895487170387i)



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