# Find Maximum and Minimum element in a Set in C++ STL

• Difficulty Level : Medium
• Last Updated : 20 Jul, 2022

Given a Set, the task is to find the maximum and minimum element of this set in C++ STL. Examples:

```Input: set={1, 6, 15, 10, 5}
Output: max = 15, min = 1

Input: set={10, 20, 30, 40, 50, 60}
Output: max = 60, min = 10```
• Using set.begin() and set.end() methods Approach: Elements in a set are stored in sorted order. So the minimum element of the set will reside in the first element and the maximum element in the last element. Therefore, this first and last element can be fetched with the help of set.begin() and set.end() methods respectively. Program:

## CPP

 `#include ``using` `namespace` `std;` `// Function to print the set``void` `printSet(set<``int``> my_set)``{` `    ``// Print the set``    ``cout << ``"Set: "``;``    ``for` `(``auto` `i : my_set)``        ``cout << i << ``" "``;` `    ``cout << ``'\n'``;``}` `// Function to find the maximum element``int` `findMax(set<``int``> my_set)``{` `    ``// Get the maximum element``    ``int` `max_element;``    ``if` `(!my_set.empty())``        ``max_element = *(my_set.rbegin());` `    ``// return the maximum element``    ``return` `max_element;``}` `// Function to find the minimum element``int` `findMin(set<``int``> my_set)``{` `    ``// Get the minimum element``    ``int` `min_element;``    ``if` `(!my_set.empty())``        ``min_element = *my_set.begin();` `    ``// return the minimum element``    ``return` `min_element;``}` `int` `main()``{` `    ``// Get the set``    ``set<``int``> my_set;` `    ``// Add the elements in the set``    ``my_set.insert(1);``    ``my_set.insert(6);``    ``my_set.insert(15);``    ``my_set.insert(10);``    ``my_set.insert(5);` `    ``// Print the set``    ``printSet(my_set);` `    ``// Get the minimum element``    ``cout << ``"Minimum element: "``        ``<< findMin(my_set)``        ``<< endl;` `    ``// Get the maximum element``    ``cout << ``"Maximum element: "``        ``<< findMax(my_set)``        ``<< endl;``}`

Output:

```Set: 1 5 6 10 15
Minimum element: 1
Maximum element: 15```
• Using set.rbegin() and set.rend() methods Approach: Elements in a set are stored in sorted order. So the minimum element of the set will reside in the first element and the maximum element in the last element. Therefore, this first and last element can be fetched with the help of set.rend() and set.rbegin() methods respectively. Program:

## CPP

 `#include ``using` `namespace` `std;` `// Function to print the set``void` `printSet(set<``int``> my_set)``{` `    ``// Print the set``    ``cout << ``"Set: "``;``    ``for` `(``auto` `i : my_set)``        ``cout << i << ``" "``;` `    ``cout << ``'\n'``;``}` `// Function to find the maximum element``int` `findMax(set<``int``> my_set)``{` `    ``// Get the maximum element``    ``int` `max_element;``    ``if` `(!my_set.empty())``        ``max_element = *my_set.rbegin();` `    ``// return the maximum element``    ``return` `max_element;``}` `// Function to find the minimum element``int` `findMin(set<``int``> my_set)``{` `    ``// Get the minimum element``    ``int` `min_element;``    ``if` `(!my_set.empty())``        ``min_element = *(--my_set.rend());` `    ``// return the minimum element``    ``return` `min_element;``}` `int` `main()``{` `    ``// Get the set``    ``set<``int``> my_set;` `    ``// Add the elements in the set``    ``my_set.insert(1);``    ``my_set.insert(6);``    ``my_set.insert(15);``    ``my_set.insert(10);``    ``my_set.insert(5);` `    ``// Print the set``    ``printSet(my_set);` `    ``// Get the minimum element``    ``cout << ``"Minimum element: "``        ``<< findMin(my_set)``        ``<< endl;` `    ``// Get the maximum element``    ``cout << ``"Maximum element: "``        ``<< findMax(my_set)``        ``<< endl;``}`

Output:

```Set: 1 5 6 10 15
Minimum element: 1
Maximum element: 15```

Time Complexity: Both the methods are of constant time complexity. In set the maximum element is stored at last so we can return the last element using rbegin() method in O(1) time. Similarly, for minimum element using begin() method in O(1) time.

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