How to find the minimum and maximum element of an Array using STL in C++?
Last Updated :
07 Jul, 2022
Given an array arr[], find the minimum and maximum element of this array using STL in C++.
Example:
Input: arr[] = {1, 45, 54, 71, 76, 12}
Output: min = 1, max = 76
Input: arr[] = {10, 7, 5, 4, 6, 12}
Output: min = 4, max = 12
Approach:
- Min or Minimum element can be found with the help of *min_element() function provided in STL.
- Max or Maximum element can be found with the help of *max_element() function provided in STL.
Syntax:
*min_element (first, last);
*max_element (first, last);
To use *min_element() and *max_element() you must include “algorithm” as a header file.
The range used is [first, last], which contains all the elements between first and last, including the element pointed by first but not the element pointed by last.
Below is the implementation of the above approach:
CPP
#include <bits/stdc++.h>
using namespace std;
int main()
{
int arr[] = { 1, 45, 54, 71, 76, 12 };
int n = sizeof (arr) / sizeof (arr[0]);
cout << "Array: " ;
for ( int i = 0; i < n; i++)
cout << arr[i] << " " ;
cout << "\nMin Element = "
<< *min_element(arr, arr + n);
cout << "\nMax Element = "
<< *max_element(arr, arr + n);
int &min = *min_element(arr,arr+n );
int &max = *max_element(arr,arr+n );
cout<< "\nFinding the Element using address variable" ;
cout<< "\nMin Element = " <<min;
cout<< "\nMax Element = " <<max;
return 0;
}
|
Output
Array: 1 45 54 71 76 12
Min Element = 1
Max Element = 76
Finding the Element using address variable
Min Element = 1
Max Element = 76
Time Complexity: O(N)
Auxiliary Space: O(1)
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