# Find if an array contains a string with one mismatch

Given a string and array of strings, find whether the array contains a string with one character difference from the given string. Array may contain strings of different lengths.

Examples:

```Input : str = "banana"
arr[] = {"bana", "apple", "banaba",
bonanzo", "banamf"}
Output :True
Explanation:-There is only a one character difference
between banana and banaba

Input : str = "banana"
arr[] = {"bana", "apple", "banabb", bonanzo",
"banamf"}
Output : False
```

## Recommended: Please solve it on “PRACTICE ” first, before moving on to the solution.

We traverse through given string and check for every string in arr. Follow the two steps as given below for every string contained in arr:-
1) Check whether the string contained in arr is of the same length as the target string.
2) If yes, then check if there is only one character mismatch, if yes then return true else return false.

## C++

 `// C++ program to find if given string is present ` `// with one mismatch. ` `#include ` `using` `namespace` `std; ` ` `  `bool` `check(vector list, string s) ` `{ ` `    ``int` `n = (``int``)list.size(); ` ` `  `    ``// If the array is empty     ` `    ``if` `(n == 0)  ` `        ``return` `false``; ` ` `  `    ``for` `(``int` `i = 0; i < n; i++) { ` ` `  `        ``// If sizes are same  ` `        ``if` `(list[i].size() != s.size()) ` `            ``continue``; ` `  `  `        ``bool` `diff = ``false``; ` `        ``for` `(``int` `j = 0; j < (``int``)list[i].size(); j++) { ` ` `  `            ``if` `(list[i][j] != s[j]) { ` `     `  `                ``// If first mismatch    ` `                ``if` `(!diff) ` `                    ``diff = ``true``; ` ` `  `                ``// Second mismatch ` `                ``else` `{ ` `                    ``diff = ``false``; ` `                    ``break``; ` `                ``} ` `            ``} ` `        ``} ` ` `  `        ``if` `(diff) ` `            ``return` `true``; ` `    ``} ` ` `  `    ``return` `false``; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``vector s; ` `    ``s.push_back(``"bana"``); ` `    ``s.push_back(``"apple"``); ` `    ``s.push_back(``"banacb"``); ` `    ``s.push_back(``"bonanza"``); ` `    ``s.push_back(``"banamf"``); ` ` `  `    ``cout << check(s, ``"banana"``); ` `    ``return` `0; ` `} `

## Java

 `import` `java.util.*; ` ` `  `// Java program to find if ` `// given string is present ` `// with one mismatch. ` `class` `GFG ` `{ ` ` `  `    ``static` `boolean` `check(Vector list, String s)  ` `    ``{ ` `        ``int` `n = (``int``) list.size(); ` ` `  `        ``// If the array is empty  ` `        ``if` `(n == ``0``)  ` `        ``{ ` `            ``return` `false``; ` `        ``} ` ` `  `        ``for` `(``int` `i = ``0``; i < n; i++) ` `        ``{ ` ` `  `            ``// If sizes are same  ` `            ``if` `(list.get(i).length() != s.length()) ` `            ``{ ` `                ``continue``; ` `            ``} ` ` `  `            ``boolean` `diff = ``false``; ` `            ``for` `(``int` `j = ``0``; j < (``int``) list.get(i).length(); j++)  ` `            ``{ ` ` `  `                ``if` `(list.get(i).charAt(j) != s.charAt(j))  ` `                ``{ ` ` `  `                    ``// If first mismatch  ` `                    ``if` `(!diff) ` `                    ``{ ` `                        ``diff = ``true``; ` `                    ``}  ` `                     `  `                    ``// Second mismatch ` `                    ``else`  `                    ``{ ` `                        ``diff = ``false``; ` `                        ``break``; ` `                    ``} ` `                ``} ` `            ``} ` ` `  `            ``if` `(diff) { ` `                ``return` `true``; ` `            ``} ` `        ``} ` ` `  `        ``return` `false``; ` `    ``} ` ` `  `    ``// Driver code ` `    ``public` `static` `void` `main(String[] args)  ` `    ``{ ` `        ``Vector s = ``new` `Vector<>(); ` `        ``s.add(``"bana"``); ` `        ``s.add(``"apple"``); ` `        ``s.add(``"banacb"``); ` `        ``s.add(``"bonanza"``); ` `        ``s.add(``"banamf"``); ` ` `  `        ``System.out.println(check(s, ``"banana"``) == ``true` `? ``1` `: ``0``); ` `    ``} ` `} ` ` `  `/* This code contributed by PrinciRaj1992 */`

## Python3

 `# Python 3 program to find if given  ` `# string is present with one mismatch. ` ` `  `def` `check(``list``, s): ` `    ``n ``=` `len``(``list``) ` ` `  `    ``# If the array is empty  ` `    ``if` `(n ``=``=` `0``):  ` `        ``return` `False` ` `  `    ``for` `i ``in` `range``(``0``, n, ``1``): ` `         `  `        ``# If sizes are same  ` `        ``if` `(``len``(``list``[i]) !``=` `len``(s)): ` `            ``continue` ` `  `        ``diff ``=` `False` `        ``for` `j ``in` `range``(``0``, ``len``(``list``[i]), ``1``): ` `            ``if` `(``list``[i][j] !``=` `s[j]): ` ` `  `                ``# If first mismatch  ` `                ``if` `(diff ``=``=` `False``): ` `                    ``diff ``=` `True` ` `  `                ``# Second mismatch ` `                ``else``: ` `                    ``diff ``=` `False` `                    ``break` `                 `  `        ``if` `(diff): ` `            ``return` `True` ` `  `    ``return` `False` ` `  `# Driver code ` `if` `__name__ ``=``=` `'__main__'``: ` `    ``s ``=` `[] ` `    ``s.append(``"bana"``) ` `    ``s.append(``"apple"``) ` `    ``s.append(``"banacb"``) ` `    ``s.append(``"bonanza"``) ` `    ``s.append(``"banamf"``) ` ` `  `    ``print``(``int``(check(s, ``"banana"``))) ` ` `  `# This code is contributed by ` `# Sahil_shelangia `

## C#

// C# program to find if
// given string is present
// with one mismatch.
using System;
using System.Collections.Generic;
public class GFG
{

static bool check(List list, String s)
{
int n = (int) list.Count;

// If the array is empty
if (n == 0)
{
return false;
}

for (int i = 0; i < n; i++) { // If sizes are same if (list[i].Length != s.Length) { continue; } bool diff = false; for (int j = 0; j < (int) list[i].Length; j++) { if (list[i][j] != s[j]) { // If first mismatch if (!diff) { diff = true; } // Second mismatch else { diff = false; break; } } } if (diff) { return true; } } return false; } // Driver code public static void Main(String[] args) { List s = new List();

Console.WriteLine(check(s, “banana”) == true ? 1 : 0);
}
}
// This code has been contributed by 29AjayKumar

Output:

```0
```

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