# Divide two integers without using multiplication, division and mod operator | Set2

Given two integers say a and b. Find the quotient after dividing a by b without using multiplication, division and mod operator.

Examples:

```Input: a = 10, b = 3
Output: 3

Input: a = 43, b = -8
Output: -5
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

This problem has been already discussed here. In this post, a different approach is discussed.

Approach :

1. Let a/b = c.
2. Take log on both sides
3. log(a) – log(b) = log(c)
4. Now Log of RHS can be written as exp in LHS
5. Final formula is : exp(log(a) – log(b)) = c

## C++

 `// C++ program for above approach ` `#include ` `using` `namespace` `std; ` ` `  `// Returns the quotient of dividend/divisor. ` `void` `Divide(``int` `a, ``int` `b) ` `{ ` `    ``long` `long` `dividend = (``long` `long``)a; ` `    ``long` `long` `divisor = (``long` `long``)b; ` ` `  `    ``// Calculate sign of divisor i.e., ` `    ``// sign will be negative only if ` `    ``// either one of them is negative ` `    ``// otherwise it will be positive ` ` `  `    ``long` `long` `sign = (dividend < 0) ^ (divisor < 0) ? -1 : 1; ` ` `  `    ``// Remove signs of dividend and divisor ` `    ``dividend = ``abs``(dividend); ` `    ``divisor = ``abs``(divisor); ` ` `  `    ``// Zero division Exception. ` `    ``if` `(divisor == 0) { ` `        ``cout << ``"Cannot Divide by 0"` `<< endl; ` `        ``return``; ` `    ``} ` ` `  `    ``if` `(dividend == 0) { ` `        ``cout << a << ``" / "` `<< b << ``" is equal to : "`  `             ``<< 0 << endl; ` `        ``return``; ` `    ``} ` ` `  `    ``if` `(divisor == 1) { ` `        ``cout << a << ``" / "` `<< b << ``" is equal to : "`  `             ``<< sign * dividend << endl; ` `        ``return``; ` `    ``} ` ` `  `    ``// Using Formula derived above. ` `    ``cout << a << ``" / "` `<< b << ``" is equal to : "` `         ``<< sign * ``exp``(``log``(dividend) - ``log``(divisor)) ` `         ``<< endl; ` `} ` ` `  `// Drivers code ` `int` `main() ` `{ ` `    ``int` `a = 10, b = 5; ` ` `  `    ``Divide(a, b); ` ` `  `    ``a = 49, b = -7; ` `    ``Divide(a, b); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program for ` `// above approach ` `import` `java.io.*; ` ` `  `class` `GFG ` `{ ` `static` `void` `Divide(``int` `a, ``int` `b) ` `{ ` `    ``long` `dividend = (``long``)a; ` `    ``long` `divisor = (``long``)b; ` ` `  `    ``// Calculate sign of divisor i.e., ` `    ``// sign will be negative only if ` `    ``// either one of them is negative ` `    ``// otherwise it will be positive ` ` `  `    ``long` `sign = (dividend < ``0``) ^  ` `                ``(divisor < ``0``) ? -``1` `: ``1``; ` ` `  `    ``// Remove signs of  ` `    ``// dividend and divisor ` `    ``dividend = Math.abs(dividend); ` `    ``divisor = Math.abs(divisor); ` ` `  `    ``// Zero division Exception. ` `    ``if` `(divisor == ``0``) ` `    ``{ ` `        ``System.out.println(``"Cannot Divide by 0"``); ` `        ``return``; ` `    ``} ` ` `  `    ``if` `(dividend == ``0``)  ` `    ``{ ` `        ``System.out.println(a + ``" / "` `+ b +  ` `                            ``" is equal to : "` `+ ``0``); ` `        ``return``; ` `    ``} ` ` `  `    ``if` `(divisor == ``1``)  ` `    ``{ ` `        ``System.out.println(a + ``" / "` `+ b +  ` `                           ``" is equal to : "` `+  ` `                             ``sign * dividend); ` `        ``return``; ` `    ``} ` ` `  `    ``// Using Formula ` `    ``// derived above. ` `    ``System.out.println(a + ``" / "` `+ b + ``" is equal to : "` `+  ` `                                         ``Math.floor(sign *  ` `                            ``(Math.exp(Math.log(dividend) -  ` `                             ``Math.log(divisor))))); ` `} ` ` `  `// Driver code ` `public` `static` `void` `main (String[] args)  ` `{ ` `int` `a = ``10``, b = ``5``; ` ` `  `Divide(a, b); ` ` `  `a = ``49``; b = -``7``; ` `Divide(a, b); ` `} ` `} ` ` `  `// This code is contributed ` `// by shiv_bhakt. `

## Python3

 `# Python3 program ` `# for above approach ` `import` `math ` `def` `Divide(a, b): ` `    ``dividend ``=` `a; ` `    ``divisor ``=` `b; ` ` `  `    ``# Calculate sign of divisor  ` `    ``# i.e., sign will be negative  ` `    ``# only if either one of them  ` `    ``# is negative otherwise it ` `    ``# will be positive ` ` `  `    ``sign ``=` `-``1` `if` `((dividend < ``0``) ^  ` `                  ``(divisor < ``0``)) ``else` `1``; ` ` `  `    ``# Remove signs of  ` `    ``# dividend and divisor ` `    ``dividend ``=` `abs``(dividend); ` `    ``divisor ``=` `abs``(divisor); ` ` `  `    ``# Zero division Exception. ` `    ``if` `(divisor ``=``=` `0``):  ` `        ``print``(``"Cannot Divide by 0"``); ` ` `  `    ``if` `(dividend ``=``=` `0``):  ` `        ``print``(a, ``"/"``, b, ``"is equal to :"``, ``0``); ` ` `  `    ``if` `(divisor ``=``=` `1``): ` `        ``print``(a, ``"/"``, b, ``"is equal to :"``,  ` `                      ``(sign ``*` `dividend)); ` ` `  `    ``# Using Formula  ` `    ``# derived above. ` `    ``print``(a, ``"/"``, b, ``"is equal to :"``,  ` `          ``math.floor(sign ``*` `math.exp(math.log(dividend) ``-`  `                                     ``math.log(divisor)))); ` ` `  `# Driver code ` `a ``=` `10``; ` `b ``=` `5``; ` ` `  `Divide(a, b); ` ` `  `a ``=` `49``; ` `b ``=` `-``7``; ` `Divide(a, b); ` ` `  `# This code is contributed ` `# by mits `

## C#

 `// C# program for ` `// above approach ` `using` `System; ` ` `  `class` `GFG ` `{ ` `static` `void` `Divide(``int` `a, ``int` `b) ` `{ ` `    ``long` `dividend = (``long``)a; ` `    ``long` `divisor = (``long``)b; ` ` `  `    ``// Calculate sign of divisor  ` `    ``// i.e., sign will be negative  ` `    ``// only if either one of them  ` `    ``// is negative otherwise it ` `    ``// will be positive ` ` `  `    ``long` `sign = (dividend < 0) ^  ` `                ``(divisor < 0) ? -1 : 1; ` ` `  `    ``// Remove signs of  ` `    ``// dividend and divisor ` `    ``dividend = Math.Abs(dividend); ` `    ``divisor = Math.Abs(divisor); ` ` `  `    ``// Zero division Exception. ` `    ``if` `(divisor == 0) ` `    ``{ ` `        ``Console.WriteLine(``"Cannot Divide by 0"``); ` `        ``return``; ` `    ``} ` ` `  `    ``if` `(dividend == 0)  ` `    ``{ ` `        ``Console.WriteLine(a + ``" / "` `+ b +  ` `                          ``" is equal to : "` `+ 0); ` `        ``return``; ` `    ``} ` ` `  `    ``if` `(divisor == 1)  ` `    ``{ ` `        ``Console.WriteLine(a + ``" / "` `+ b +  ` `                          ``" is equal to : "` `+  ` `                            ``sign * dividend); ` `        ``return``; ` `    ``} ` ` `  `    ``// Using Formula ` `    ``// derived above. ` `    ``Console.WriteLine(a + ``" / "` `+ b + ``" is equal to : "` `+  ` `                                        ``Math.Floor(sign *  ` `                           ``(Math.Exp(Math.Log(dividend) -  ` `                                   ``Math.Log(divisor))))); ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main ()  ` `{ ` `    ``int` `a = 10, b = 5; ` `     `  `    ``Divide(a, b); ` `     `  `    ``a = 49; b = -7; ` `    ``Divide(a, b); ` `} ` `} ` ` `  `// This code is contributed ` `// by shiv_bhakt. `

## PHP

 ` `

Output:

```10 / 5 is equal to : 2
49 / -7 is equal to : -7
```

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