C++ Program to Copy the Contents of One Array Into Another in the Reverse Order

Given an array, the task is to copy these array elements into another array in reverse array.
Examples:

Input: array: 1 2 3 4 5 
Output: 5 4 3 2 1 

Input: array: 10 20 30 40 50 
Output: 50 40 30 20 10  

Let len be the length of original array. We copy every element original_arr[i] to copy_arr[n-i-1] to get reverse in copy_arr[]. 

C++

// C program to copy the contents
// of one array into another
// in the reverse order

#include <stdio.h>

// Function to print the array
void printArray(int arr[], int len)
{
    int i;
    for (i = 0; i < len; i++) {
        printf("%d ", arr[i]);
    }
}

// Driver code
int main()
{
    int original_arr[] = {1, 2, 3, 4, 5};
    int len = sizeof(original_arr)/sizeof(original_arr[0]);

    int copied_arr[len], i, j;

    // Copy the elements of the array
    // in the copied_arr in Reverse Order
    for (i = 0; i < len; i++) {
        copied_arr[i] = original_arr[len - i - 1];
    }

    // Print the original_arr
    printf("
Original array: ");
    printArray(original_arr, len);

    // Print the copied array
    printf("
Resultant array: ");
    printArray(copied_arr, len);

    return 0;
}

Output:

Original array: 1 2 3 4 5 
Resultant array: 5 4 3 2 1

Time Complexity: O(len)

Auxiliary Space: O(len)