Check whether a given number is even or odd

Given a number, check whether it is even or odd.

Examples :

Input: 2 
Output: even

Input: 5
Output: odd

One simple solution is to find the remainder after dividing by 2. 

C++

// A simple C++ program to
// check for even or odd
#include <iostream>
using namespace std;

// Returns true if n is
// even, else odd
bool isEven(int n) { return (n % 2 == 0); }

// Driver code
int main()
{
    int n = 101;
    isEven(n) ? cout << "Even" : cout << "Odd";

    return 0;
}

Java

// Java program  to
// check for even or odd

class GFG
{
    // Returns true if n is even, else odd
    public static boolean isEven(int n)
    {
        return (n % 2 == 0);
    }

    // Driver code
    public static void main(String[] args)
    {
        int n = 101;
        if(isEven(n) == true)
            System.out.print("Even");
        else
            System.out.print("Odd");
    }
}

// This code is contributed by rishabh_jain

Python3

# A simple Python3 code
# to check for even or odd

# Returns true if n is even, else odd
def isEven(n):
    return (n % 2 == 0)

# Driver code
n = 101
print("Even" if isEven(n) else "Odd")

# This code is contributed by "Sharad_Bhardwaj".

C#

// C# program to
// check for even or odd
using System;

class GFG
{
    // Returns true if n is even, else odd
    public static bool isEven(int n)
    {
        return (n % 2 == 0);
    }

    // Driver code
    public static void Main()
    {
        int n = 101;
        if(isEven(n) == true)
            Console.WriteLine("Even");
        else
            Console.WriteLine("Odd");
    }
}

// This code is contributed by vt_m

PHP

<?php
// A simple PHP program to
// check for even or odd

// Returns true if n is
// even, else odd
function isEven($n)
{
    return ($n % 2 == 0);
}

// Driver code
$n = 101;
if(isEven != true)
    echo "Even";
    else
    echo "Odd";

// This code is contributed by Ajit
?>

Javascript

<script>

// A simple Javascript program to
// check for even or odd


// Returns true if n is
// even, else odd
function isEven(n) { return (n % 2 == 0); }

// Driver code

    let n = 101;
    isEven(n) ? document.write("Even") :document.write("Odd");


// This code is contributed by Mayank Tyagi

</script>

Output

Odd

Time Complexity: O(1)
Auxiliary Space: O(1)

A better solution is to use bitwise operators. We need to check whether last bit is 1 or not. If last bit is 1 then number is odd, otherwise always even.

Explanation: 

 input : 5    // odd
   00000101              
 & 00000001                
--------------                
   00000001       
--------------

input : 8     //even
   00001000              
 & 00000001                 
--------------               
   00000000        
--------------

Below is the implementation of the idea. 

C++

// A simple C++ program to
// check for even or odd
#include <iostream>
using namespace std;

// Returns true if n is
// even, else odd
bool isEven(int n)
{

// n & 1 is 1, then
// odd, else even
return (!(n & 1));
}

// Driver code
int main()
{
int n = 101;
isEven(n)? cout << "Even" :
           cout << "Odd";

return 0;
}

C

#include <stdio.h>
#include <math.h>

int main(){
  int n = 101;
  if (n%2==0){
    printf("Even");
  }
  else{
    printf("Odd");
  }
 return 0;
}

Java

// Java program to
// check for even or odd

class GFG
{
    // Returns true if n
    // is even, else odd
    public static boolean isEven(int n)
    {
        if((n & 1) == 0)
            return true;
        else
            return false;
    }

    // Driver code
    public static void main(String[] args)
    {
        int n = 101;
        if(isEven(n) == true)
            System.out.print("Even");
        else
            System.out.print("Odd");
    }
}

// This code is contributed by rishabh_jain

Python3

# A Python3 code program
# to check for even or odd

# Returns true if n is even, else odd
def isEven(n):

    # n&1 is 1, then odd, else even
    return (not(n & 1))

# Driver code
n = 101;
print("Even" if isEven(n) else "Odd")

# This code is contributed by "Sharad_Bhardwaj".

C#

// C# program  to
// check for even or odd
using System;

class GFG
{
    // Returns true if n
    // is even, else odd
    public static bool isEven(int n)
    {
        if((n & 1) == 0)
            return true;
        else
            return false;
    }

    // Driver code
    public static void Main()
    {
        int n = 101;
        if(isEven(n) == true)
            Console.WriteLine("Even");
        else
            Console.WriteLine("Odd");
    }
}

// This code is contributed by vt_m.

PHP

<?php
// A simple PHP program to
// check for even or odd

// Returns true if n is
// even, else odd
function isEven($n)
{
    return (!($n & 1));
}

// Driver code
$n = 101;
if(isEven($n) == true)
    echo "Even";
else
    echo "Odd";

// This code is contributed by Smitha
?>

Javascript

<script>
// A simple JavaScript program to
// check for even or odd

// Returns true if n is
// even, else odd
function isEven(n)
{

    // n & 1 is 1, then
    // odd, else even
    return (!(n & 1));
}

// Driver code
let n = 101;
isEven(n)? document.write("Even") :
        document.write("Odd");

// This code is contributed by Manoj.
</script>

Output

Odd

Time Complexity: O(1)
Auxiliary Space: O(1)

This article is contributed by Prabhat Raushan. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.