Given a number, check whether it is even or odd.
Examples :
Input: 2 Output: even Input: 5 Output: odd
One simple solution is to find remainder after dividing by 2.
C++
// A simple C++ program to // check for even or odd #include <iostream> using namespace std; // Returns true if n is // even, else odd bool isEven(int n) { return (n % 2 == 0); } // Driver code int main() { int n = 101; isEven(n)? cout << "Even" : cout << "Odd"; return 0; } |
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Java
// Java program program to // check for even or odd class GFG { // Returns true if n is even, else odd public static boolean isEven(int n) { return (n % 2 == 0); } // Driver code public static void main(String[] args) { int n = 101; if(isEven(n) == true) System.out.print("Even"); else System.out.print("Odd"); } } // This code is contributed by rishabh_jain |
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Python3
# A simple Python3 code # to check for even or odd # Returns true if n is even, else odd def isEven(n): return (n % 2 == 0) # Driver code n = 101print("Even" if isEven(n) else "Odd") # This code is contributed by "Sharad_Bhardwaj". |
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C#
// C# program program to // check for even or odd using System; class GFG { // Returns true if n is even, else odd public static bool isEven(int n) { return (n % 2 == 0); } // Driver code public static void Main() { int n = 101; if(isEven(n) == true) Console.WriteLine("Even"); else Console.WriteLine("Odd"); } } // This code is contributed by vt_m |
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PHP
<?php // A simple PHP program to // check for even or odd // Returns true if n is // even, else odd function isEven($n) { return ($n % 2 == 0); } // Driver code $n = 101; if(isEven != true) echo "Even"; else echo "Odd"; // This code is contributed by Ajit ?> |
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Output :
Odd
A better solution is to use bitwise operators. We need to check whether last bit is 1 or not. If last bit is 1 then number is odd, otherwise always even.
Explanation:
input : 5 // odd 00000101 & 00000001 -------------- 00000001 -------------- input : 8 //even 00001000 & 00000001 -------------- 00000000 --------------
Below is the implementation of the idea.
C++
// A simple C++ program to // check for even or odd #include <iostream> using namespace std; // Returns true if n is // even, else odd bool isEven(int n) { // n & 1 is 1, then // odd, else even return (!(n & 1)); } // Driver code int main() { int n = 101; isEven(n)? cout << "Even" : cout << "Odd"; return 0; } |
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Java
// Java program program to // check for even or odd class GFG { // Returns true if n // is even, else odd public static boolean isEven(int n) { if((n & 1) == 0) return true; else return false; } // Driver code public static void main(String[] args) { int n = 101; if(isEven(n) == true) System.out.print("Even"); else System.out.print("Odd"); } } // This code is contributed by rishabh_jain |
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Python3
# A Python3 code program # to check for even or odd # Returns true if n is even, else odd def isEven(n): # n&1 is 1, then odd, else even return (not(n & 1)) # Driver code n = 101; print("Even" if isEven(n) else "Odd") # This code is contributed by "Sharad_Bhardwaj". |
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C#
// C# program program to // check for even or odd using System; class GFG { // Returns true if n // is even, else odd public static bool isEven(int n) { if((n & 1) == 0) return true; else return false; } // Driver code public static void Main() { int n = 101; if(isEven(n) == true) Console.WriteLine("Even"); else Console.WriteLine("Odd"); } } // This code is contributed by vt_m. |
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PHP
<?php // A simple PHP program to // check for even or odd // Returns true if n is // even, else odd function isEven($n) { return (!($n & 1)); } // Driver code $n = 101; if(isEven($n) == true) echo "Even"; else echo "Odd"; // This code is contributed by Smitha ?> |
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Output :
Odd
This article is contributed by Prabhat Raushan. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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