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Check if two arrays can be made equal by reversing subarrays multiple times
• Last Updated : 22 Apr, 2021

Given two arrays A[] and B[], the task is to check if array B can be made equal to A by reversing the subarrays of B by any number of times.

Examples:

Input:  A[] =  {1 2 3}, B[] =  {3 1 2}
Output: Yes
Explanation:
Reverse subarrays in array B as shown below:
Reverse subarray [3, 1], B becomes [1, 3, 2]
Reverse subarray [3, 2], B becomes [1, 2, 3] = A
There are multiple ways to convert B to A.
Input:  A[] = {1 2 3}, B[] = {3 4 1 }
Output: No

Approach: Since we have to make array B equal to array A only by reversing any sub array any number of times, Therefore it is possible only when both the arrays are anagrams. To check if both arrays are anagrams, we will sort both the arrays and check if at any index elements are not same then we will return false, otherwise we will return true at the end.

Below implementation of the above approach:

## C++

 `// C++ implementation to check if``// two arrays can be made equal` `#include ``using` `namespace` `std;` `// Function to check if array B``// can be made equal to array A``bool` `canMadeEqual(``int` `A[],``                  ``int` `B[], ``int` `n)``{``    ``// sort both the arrays``    ``sort(A, A + n);``    ``sort(B, B + n);` `    ``// Check if both the arrays``    ``// are equal or not``    ``for` `(``int` `i = 0; i < n; i++)``        ``if` `(A[i] != B[i])``            ``return` `false``;``    ``return` `true``;``}` `// Driver Code``int` `main()``{``    ``int` `A[] = { 1, 2, 3 };``    ``int` `B[] = { 1, 3, 2 };``    ``int` `n = ``sizeof``(A) / ``sizeof``(A);``    ``if` `(canMadeEqual(A, B, n))``        ``cout << ``"Yes"``;``    ``else``        ``cout << ``"No"``;` `    ``return` `0;``}`

## C

 `// C implementation to check if ``// two arrays can be made equal``#include``#include` `int` `sort(``int` `a[],``int` `n)``{``    ``int` `i, j, tmp;``    ``for``(i = 0; i < n; i++)``    ``{``        ``for``(j = i + 1; j < n; j++)``        ``{``            ``if``(a[j]

## Java

 `// Java implementation to check if``// two arrays can be made equal``import` `java.util.*;` `class` `GFG{``    ` `// Function to check if array B``// can be made equal to array A``public` `static` `boolean` `canMadeEqual(``int``[] A,``                                   ``int``[] B,``                                   ``int` `n)``{``    ` `    ``// Sort both the arrays``    ``Arrays.sort(A);``    ``Arrays.sort(B);` `    ``// Check if both the arrays``    ``// are equal or not``    ``for``(``int` `i = ``0``; i < n; i++)``    ``{``        ``if` `(A[i] != B[i])``        ``{``            ``return` `false``;``        ``}``    ``}``    ``return` `true``;``}` `// Driver code``public` `static` `void` `main(String[] args)``{``    ``int` `A[] = { ``1``, ``2``, ``3` `};``    ``int` `B[] = { ``1``, ``3``, ``2` `};``    ``int` `n = A.length;``    ` `    ``if` `(canMadeEqual(A, B, n))``        ``System.out.print(``"Yes"``);``    ``else``        ``System.out.print(``"No"``);``}``}` `// This code is contributed by divyeshrabadiya07`

## Python3

 `# Python3 implementation to check if``# two arrays can be made equal` `# Function to check if array B``# can be made equal to array A``def` `canMadeEqual(A, B, n):``  ` `  ``# Sort both the arrays``  ``A.sort()``  ``B.sort()` `  ``# Check if both the arrays``  ``# are equal or not``  ``for` `i ``in` `range``(n):``    ``if` `(A[i] !``=` `B[i]):``      ``return` `False``    ` `  ``return` `True` `# Driver Code``if` `__name__ ``=``=` `"__main__"``:``  ` `  ``A ``=` `[ ``1``, ``2``, ``3` `]``  ``B ``=` `[ ``1``, ``3``, ``2` `]``  ``n ``=` `len``(A)` `  ``if` `(canMadeEqual(A, B, n)):``    ``print``( ``"Yes"``)``  ``else``:``    ``print``(``"No"``)` `# This code is contributed by chitranayal`

## C#

 `// C# implementation to check if``// two arrays can be made equal``using` `System;` `class` `GFG{` `// Function to check if array B``// can be made equal to array A``static` `bool` `canMadeEqual(``int``[] A,``                         ``int``[] B,``                         ``int` `n)``{``    ` `    ``// Sort both the arrays``    ``Array.Sort(A);``    ``Array.Sort(B);` `    ``// Check if both the arrays``    ``// are equal or not``    ``for``(``int` `i = 0; i < n; i++)``    ``{``        ``if` `(A[i] != B[i])``        ``{``            ``return` `false``;``        ``}``    ``}``    ``return` `true``;``}` `// Driver code``public` `static` `void` `Main()``{``    ``int``[] A = { 1, 2, 3 };``    ``int``[] B = { 1, 3, 2 };``    ``int` `n = A.Length;``    ` `    ``if` `(canMadeEqual(A, B, n))``        ``Console.Write(``"Yes"``);``    ``else``        ``Console.Write(``"No"``);``}``}` `// This code is contributed by adityakumar27200`

## Javascript

 ``
Output
`Yes`

Time complexity: O(N*Log N)
Auxiliary Space: O(1)

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