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Check if the tower of sight issue occurs or not

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Given four co-ordinates A, B, C and D where towers need to be constructed, the task is to check if the tower of sight issue occurs or not. 
 

Tower of sight issue occurs if the towers at A or C lies in the line joining B and D or vice versa.


Examples: 
 

Input: A = (0, 0), B = (0, -2), C = (2, 0), D = (0, 2) 
Output: Yes 
Explanation: 
Tower A lies in the line joining B and D.
Input: A = (0, 0), B = (0, -2), C = (2, 0), D = (0, -5) 
Output: No 
Explanation: 
No intersection occurs. 
 


 


Approach: 
 

  • If A and C are parallel to the X-axis, check if B or D has y coordinate equal to that of A and C and x coordinate in between that of A and C.
  • If A and C are parallel to the Y-axis, check if B or D has x coordinate equal to that of A and C and y coordinate in between that of A and C.
  • Otherwise, check if B or D satisfies the line equation of A and C.
  • Similarly follow the above three steps to check if A or C lies in between B or D.


Below code is the implementation of the above approach: 
 

C++

// C++ program to check if tower
// of sight issue occurs or not
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to check if point p lies in
// between the line joining p1 and p2
int checkIntersection(pair<int, int> p1,
                      pair<int, int> p2,
                      pair<int, int> p)
{
    int val;
 
    // If parallel to X-axis
    if (p1.second == p2.second
        && p1.second == p.second) {
 
        if (p.first <= max(p1.first, p2.first)
            && (p.first >= min(p1.first, p2.first)))
 
            // Point p lies between p1 and p2
            return 1;
    }
 
    // If parallel to Y-axis
    if (p1.first == p2.first
        && p1.first == p.first) {
 
        if (p.second <= max(p1.second, p2.second)
            && (p.second >= min(p1.second, p2.second)))
 
            // Point p lies between p1 and p2
            return 1;
    }
 
    // If point p satisfies the equation
    // of line joining p1 and p2
    else {
        val = (p.second - p1.second)
                  * (p2.first - p1.first)
              - (p.first - p1.first)
                    * (p2.second - p1.second);
 
        if (val == 0)
            if ((p.first <= max(p1.first, p2.first)
                 && (p.first >= min(p1.first, p2.first)))
                && (p.second <= max(p1.second, p2.second)
                    && (p.second >= min(p1.second, p2.second))))
                return 1;
    }
 
    return 0;
}
 
// Function to check if tower
// of sight issue occurred
void towerOfSight(pair<int, int> a,
                  pair<int, int> b,
                  pair<int, int> c,
                  pair<int, int> d)
{
    int flag = 0;
 
    if (checkIntersection(a, c, b))
 
        // B lies between AC
        flag = 1;
 
    else if (checkIntersection(a, c, d))
 
        // D lies between AC
        flag = 1;
 
    else if (checkIntersection(b, d, a))
 
        // A lies between BD
        flag = 1;
 
    else if (checkIntersection(b, d, c))
 
        // C lies between BD
        flag = 1;
 
    flag ? cout << "Yes\n"
         : cout << "No\n";
}
 
// Driver code
int main()
{
    // Point A
    pair<int, int> a = { 0, 0 };
 
    // Point B
    pair<int, int> b = { 0, -2 };
 
    // Point C
    pair<int, int> c = { 2, 0 };
 
    // Point D
    pair<int, int> d = { 0, 2 };
 
    towerOfSight(a, b, c, d);
 
    return 0;
}

                    

Java

// Java program to check if tower
// of sight issue occurs or not
class GFG{
 
static class pair
{
    int first, second;
    public pair(int first, int second) 
    {
        this.first = first;
        this.second = second;
    }   
}
   
// Function to check if point p lies in
// between the line joining p1 and p2
static int checkIntersection(pair p1,
                      pair p2,
                      pair p)
{
    int val;
  
    // If parallel to X-axis
    if (p1.second == p2.second
        && p1.second == p.second) {
  
        if (p.first <= Math.max(p1.first, p2.first)
            && (p.first >= Math.min(p1.first, p2.first)))
  
            // Point p lies between p1 and p2
            return 1;
    }
  
    // If parallel to Y-axis
    if (p1.first == p2.first
        && p1.first == p.first) {
  
        if (p.second <= Math.max(p1.second, p2.second)
            && (p.second >= Math.min(p1.second, p2.second)))
  
            // Point p lies between p1 and p2
            return 1;
    }
  
    // If point p satisfies the equation
    // of line joining p1 and p2
    else {
        val = (p.second - p1.second)
                  * (p2.first - p1.first)
              - (p.first - p1.first)
                    * (p2.second - p1.second);
  
        if (val == 0)
            if ((p.first <= Math.max(p1.first, p2.first)
                 && (p.first >= Math.min(p1.first, p2.first)))
                && (p.second <= Math.max(p1.second, p2.second)
                    && (p.second >= Math.min(p1.second, p2.second))))
                return 1;
    }
  
    return 0;
}
  
// Function to check if tower
// of sight issue occurred
static void towerOfSight(pair a,
                  pair b,
                  pair c,
                  pair d)
{
    int flag = 0;
  
    if (checkIntersection(a, c, b) == 1)
  
        // B lies between AC
        flag = 1;
  
    else if (checkIntersection(a, c, d) == 1)
  
        // D lies between AC
        flag = 1;
  
    else if (checkIntersection(b, d, a) == 1)
  
        // A lies between BD
        flag = 1;
  
    else if (checkIntersection(b, d, c) == 1)
  
        // C lies between BD
        flag = 1;
  
    System.out.print(flag==1?"Yes\n":"No\n");
}
  
// Driver code
public static void main(String[] args)
{
    // Point A
    pair a = new pair( 0, 0 );
  
    // Point B
    pair b = new pair( 0, -2 );
  
    // Point C
    pair c = new pair( 2, 0 );
  
    // Point D
    pair d = new pair( 0, 2 );
  
    towerOfSight(a, b, c, d);
  
}
}
 
// This code is contributed by Rajput-Ji

                    

Python3

# Python 3 program to check if tower
# of sight issue occurs or not
  
# Function to check if point p lies in
# between the line joining p1 and p2
def checkIntersection(p1,p2,p):
  
    # If parallel to X-axis
    if (p1[1] == p2[1]
        and p1[1] == p[1]):
  
        if (p[0] <= max(p1[0], p2[0])
            and (p[0] >= min(p1[0], p2[0]))):
  
            # Point p lies between p1 and p2
            return 1
  
    # If parallel to Y-axis
    if (p1[0] == p2[0]
        and p1[0] == p[0]):
  
        if (p[1] <= max(p1[1], p2[1])
            and (p[1] >= min(p1[1], p2[1]))):
  
            # Point p lies between p1 and p2
            return 1
  
    # If point p satisfies the equation
    # of line joining p1 and p2
    else :
        val = ((p[1] - p1[1])*(p2[0] - p1[0])
              - (p[0] - p1[0])
                    * (p2[1] - p1[1]))
  
        if (val == 0):
            if ((p[0] <= max(p1[0], p2[0])
                 and (p[0] >= min(p1[0], p2[0])))
                and (p[1] <= max(p1[1], p2[1])
                    and (p[1] >= min(p1[1], p2[1])))):
                return 1
  
    return 0
  
# Function to check if tower
# of sight issue occurred
def towerOfSight(a, b, c, d):
    flag = 0
  
    if (checkIntersection(a, c, b)):
  
        # B lies between AC
        flag = 1
  
    elif (checkIntersection(a, c, d)):
        # D lies between AC
        flag = 1
  
    elif (checkIntersection(b, d, a)):
  
        # A lies between BD
        flag = 1
  
    elif (checkIntersection(b, d, c)):
  
        # C lies between BD
        flag = 1
  
    if(flag):
        print("Yes")
    else:
        print("No")
  
# Driver code
if __name__ == "__main__":
 
    # Point A
    a = [ 0, 0 ]
  
    # Point B
    b = [ 0, -2 ]
  
    # Point C
    c = [ 2, 0 ]
  
    # Point D
    d = [ 0, 2 ]
  
    towerOfSight(a, b, c, d)
  
# This code is contributed by chitranayal

                    

C#

// C# program to check if tower
// of sight issue occurs or not
using System;
 
class GFG{
  
class pair
{
    public int first, second;
    public pair(int first, int second) 
    {
        this.first = first;
        this.second = second;
    }   
}
    
// Function to check if point p lies in
// between the line joining p1 and p2
static int checkIntersection(pair p1,
                      pair p2,
                      pair p)
{
    int val;
   
    // If parallel to X-axis
    if (p1.second == p2.second
        && p1.second == p.second) {
   
        if (p.first <= Math.Max(p1.first, p2.first)
            && (p.first >= Math.Min(p1.first, p2.first)))
   
            // Point p lies between p1 and p2
            return 1;
    }
   
    // If parallel to Y-axis
    if (p1.first == p2.first
        && p1.first == p.first) {
   
        if (p.second <= Math.Max(p1.second, p2.second)
            && (p.second >= Math.Min(p1.second, p2.second)))
   
            // Point p lies between p1 and p2
            return 1;
    }
   
    // If point p satisfies the equation
    // of line joining p1 and p2
    else {
        val = (p.second - p1.second)
                  * (p2.first - p1.first)
              - (p.first - p1.first)
                    * (p2.second - p1.second);
   
        if (val == 0)
            if ((p.first <= Math.Max(p1.first, p2.first)
                 && (p.first >= Math.Min(p1.first, p2.first)))
                && (p.second <= Math.Max(p1.second, p2.second)
                    && (p.second >= Math.Min(p1.second, p2.second))))
                return 1;
    }
   
    return 0;
}
   
// Function to check if tower
// of sight issue occurred
static void towerOfSight(pair a,
                  pair b,
                  pair c,
                  pair d)
{
    int flag = 0;
   
    if (checkIntersection(a, c, b) == 1)
   
        // B lies between AC
        flag = 1;
   
    else if (checkIntersection(a, c, d) == 1)
   
        // D lies between AC
        flag = 1;
   
    else if (checkIntersection(b, d, a) == 1)
   
        // A lies between BD
        flag = 1;
   
    else if (checkIntersection(b, d, c) == 1)
   
        // C lies between BD
        flag = 1;
   
    Console.Write(flag==1?"Yes\n":"No\n");
}
   
// Driver code
public static void Main(String[] args)
{
    // Point A
    pair a = new pair( 0, 0 );
   
    // Point B
    pair b = new pair( 0, -2 );
   
    // Point C
    pair c = new pair( 2, 0 );
   
    // Point D
    pair d = new pair( 0, 2 );
   
    towerOfSight(a, b, c, d);
   
}
}
 
// This code is contributed by Princi Singh

                    

Javascript

<script>
// Javascript program to check if tower
// of sight issue occurs or not
 
// Function to check if point p lies in
// between the line joining p1 and p2
function checkIntersection(p1,p2,p)
{
    let val;
    
    // If parallel to X-axis
    if (p1[1] == p2[1]
        && p1[1] == p[1]) {
    
        if (p[0] <= Math.max(p1[0], p2[0])
            && (p[0] >= Math.min(p1[0], p2[0])))
    
            // Point p lies between p1 and p2
            return 1;
    }
    
    // If parallel to Y-axis
    if (p1[0] == p2[0]
        && p1[0] == p[0]) {
    
        if (p[1] <= Math.max(p1[1], p2[1])
            && (p[1] >= Math.min(p1[1], p2[1])))
    
            // Point p lies between p1 and p2
            return 1;
    }
    
    // If point p satisfies the equation
    // of line joining p1 and p2
    else {
        val = (p[1] - p1[1])
                  * (p2[0] - p1[0])
              - (p[0] - p1[0])
                    * (p2[1] - p1[1]);
    
        if (val == 0)
            if ((p[0] <= Math.max(p1[0], p2[0])
                 && (p[0] >= Math.min(p1[0], p2[0])))
                && (p[1] <= Math.max(p1[1], p2[1])
                    && (p[1] >= Math.min(p1[1], p2[1]))))
                return 1;
    }
    
    return 0;
}
 
// Function to check if tower
// of sight issue occurred
function towerOfSight(a,b,c,d)
{
    let flag = 0;
    
    if (checkIntersection(a, c, b) == 1)
    
        // B lies between AC
        flag = 1;
    
    else if (checkIntersection(a, c, d) == 1)
    
        // D lies between AC
        flag = 1;
    
    else if (checkIntersection(b, d, a) == 1)
    
        // A lies between BD
        flag = 1;
    
    else if (checkIntersection(b, d, c) == 1)
    
        // C lies between BD
        flag = 1;
    
    document.write(flag==1?"Yes\n":"No\n");
}
 
// Driver code
 
// Point A
let a=[0,0];
 
// Point B
let b=[0, -2 ];
 
// Point C
let c=[2, 0 ];
 
// Point D
let d=[0, 2];
towerOfSight(a, b, c, d);
 
// This code is contributed by avanitrachhadiya2155
</script>

                    

Output: 
Yes

 

Time Complexity: O(1)

Auxiliary Space: O(1)



Last Updated : 22 Nov, 2021
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