# Check if given string contains all the digits

Given a string str consisting of alphanumeric characters, the task is to check whether the string contains all the digits from 1 to 9.

Examples:

Input: str = “Geeks12345for69708”
Output: Yes
All the digits from 0 to 9 are
present in the given string.

Input: str = “Amazing1234”
Output: No

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Create a frequency array to mark the frequency of each of the digits from 0 to 9. Finally, traverse the frequency array and if there is any digit that is not present in the given string then the answer will be “No” else the answer will be “Yes”.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `const` `int` `MAX = 10; ` ` `  `// Function that returns true ` `// if ch is a digit ` `bool` `isDigit(``char` `ch) ` `{ ` `    ``if` `(ch >= ``'0'` `&& ch <= ``'9'``) ` `        ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `// Function that returns true ` `// if str contains all the ` `// digits from 0 to 9 ` `bool` `allDigits(string str, ``int` `len) ` `{ ` ` `  `    ``// To mark the present digits ` `    ``bool` `present[MAX] = { ``false` `}; ` ` `  `    ``// For every character of the string ` `    ``for` `(``int` `i = 0; i < len; i++) { ` ` `  `        ``// If the current character is a digit ` `        ``if` `(isDigit(str[i])) { ` ` `  `            ``// Mark the current digit as present ` `            ``int` `digit = str[i] - ``'0'``; ` `            ``present[digit] = ``true``; ` `        ``} ` `    ``} ` ` `  `    ``// For every digit from 0 to 9 ` `    ``for` `(``int` `i = 0; i < MAX; i++) { ` ` `  `        ``// If the current digit is ` `        ``// not present in str ` `        ``if` `(!present[i]) ` `            ``return` `false``; ` `    ``} ` ` `  `    ``return` `true``; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``string str = ``"Geeks12345for69708"``; ` `    ``int` `len = str.length(); ` ` `  `    ``if` `(allDigits(str, len)) ` `        ``cout << ``"Yes"``; ` `    ``else` `        ``cout << ``"No"``; ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach ` `class` `GFG ` `{ ` ` `  `static` `int` `MAX = ``10``; ` ` `  `// Function that returns true ` `// if ch is a digit ` `static` `boolean` `isDigit(``char` `ch) ` `{ ` `    ``if` `(ch >= ``'0'` `&& ch <= ``'9'``) ` `        ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `// Function that returns true ` `// if str contains all the ` `// digits from 0 to 9 ` `static` `boolean` `allDigits(String str, ``int` `len) ` `{ ` ` `  `    ``// To mark the present digits ` `    ``boolean` `[]present = ``new` `boolean``[MAX]; ` ` `  `    ``// For every character of the String ` `    ``for` `(``int` `i = ``0``; i < len; i++)  ` `    ``{ ` ` `  `        ``// If the current character is a digit ` `        ``if` `(isDigit(str.charAt(i))) ` `        ``{ ` ` `  `            ``// Mark the current digit as present ` `            ``int` `digit = str.charAt(i) - ``'0'``; ` `            ``present[digit] = ``true``; ` `        ``} ` `    ``} ` ` `  `    ``// For every digit from 0 to 9 ` `    ``for` `(``int` `i = ``0``; i < MAX; i++) ` `    ``{ ` ` `  `        ``// If the current digit is ` `        ``// not present in str ` `        ``if` `(!present[i]) ` `            ``return` `false``; ` `    ``} ` ` `  `    ``return` `true``; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``String str = ``"Geeks12345for69708"``; ` `    ``int` `len = str.length(); ` ` `  `    ``if` `(allDigits(str, len)) ` `        ``System.out.print(``"Yes"``); ` `    ``else` `        ``System.out.print(``"No"``); ` `} ` `} ` ` `  `// This code is contributed by 29AjayKumar `

## Python3

 `# Python3 implementation of the approach ` `MAX` `=` `10` ` `  `# Function that returns true ` `# if ch is a digit ` `def` `isDigit(ch): ` `    ``ch ``=` `ord``(ch) ` `    ``if` `(ch >``=` `ord``(``'0'``) ``and` `ch <``=` `ord``(``'9'``)): ` `        ``return` `True` `    ``return` `False` ` `  `# Function that returns true ` `# if st contains all the ` `# digits from 0 to 9 ` `def` `allDigits(st, le): ` ` `  `    ``# To mark the present digits ` `    ``present ``=` `[``False` `for` `i ``in` `range``(``MAX``)] ` ` `  `    ``# For every character of the sting ` `    ``for` `i ``in` `range``(le): ` ` `  `        ``# If the current character is a digit ` `        ``if` `(isDigit(st[i])): ` ` `  `            ``# Mark the current digit as present ` `            ``digit ``=` `ord``(st[i]) ``-` `ord``(``'0'``) ` `            ``present[digit] ``=` `True` ` `  `    ``# For every digit from 0 to 9 ` `    ``for` `i ``in` `range``(``MAX``): ` ` `  `        ``# If the current digit is ` `        ``# not present in st ` `        ``if` `(present[i] ``=``=` `False``): ` `            ``return` `False` ` `  `    ``return` `True` ` `  `# Driver code ` `st ``=` `"Geeks12345for69708"` `le ``=` `len``(st) ` ` `  `if` `(allDigits(st, le)): ` `    ``print``(``"Yes"``) ` `else``: ` `    ``print``(``"No"``) ` ` `  `# This code is contributed by Mohit Kumar `

## C#

 `// C# implementation of the approach ` `using` `System; ` ` `  `class` `GFG ` `{ ` ` `  `static` `int` `MAX = 10; ` ` `  `// Function that returns true ` `// if ch is a digit ` `static` `bool` `isDigit(``char` `ch) ` `{ ` `    ``if` `(ch >= ``'0'` `&& ch <= ``'9'``) ` `        ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `// Function that returns true ` `// if str contains all the ` `// digits from 0 to 9 ` `static` `bool` `allDigits(String str, ``int` `len) ` `{ ` ` `  `    ``// To mark the present digits ` `    ``bool` `[]present = ``new` `bool``[MAX]; ` ` `  `    ``// For every character of the String ` `    ``for` `(``int` `i = 0; i < len; i++)  ` `    ``{ ` ` `  `        ``// If the current character is a digit ` `        ``if` `(isDigit(str[i])) ` `        ``{ ` ` `  `            ``// Mark the current digit as present ` `            ``int` `digit = str[i] - ``'0'``; ` `            ``present[digit] = ``true``; ` `        ``} ` `    ``} ` ` `  `    ``// For every digit from 0 to 9 ` `    ``for` `(``int` `i = 0; i < MAX; i++) ` `    ``{ ` ` `  `        ``// If the current digit is ` `        ``// not present in str ` `        ``if` `(!present[i]) ` `            ``return` `false``; ` `    ``} ` ` `  `    ``return` `true``; ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main(String[] args) ` `{ ` `    ``String str = ``"Geeks12345for69708"``; ` `    ``int` `len = str.Length; ` ` `  `    ``if` `(allDigits(str, len)) ` `        ``Console.Write(``"Yes"``); ` `    ``else` `        ``Console.Write(``"No"``); ` `} ` `} ` ` `  `// This code is contributed by 29AjayKumar `

Output:

```Yes
```

Don’t stop now and take your learning to the next level. Learn all the important concepts of Data Structures and Algorithms with the help of the most trusted course: DSA Self Paced. Become industry ready at a student-friendly price.

My Personal Notes arrow_drop_up Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.