# Check if a given number is Pronic

• Difficulty Level : Easy
• Last Updated : 21 Jun, 2022

The numbers that can be arranged to form a rectangle are called Rectangular Numbers (also known as Pronic numbers). The first few Pronic numbers are:
0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110, 132, 156, 182, 210, 240, 272, 306, 342, 380, 420, 462 . . . . . .
Pronic number is a number which is the product of two consecutive integers, that is, a number n is a product of x and (x+1). The task is to check and print Pronic Numbers in a range.
Examples :

```Input  : 6
Output : Pronic Number
Explanation: 6 = 2 * 3 i.e 6 is a product
of two consecutive integers 2 and 3.

Input :56
Output :Pronic Number
Explanation: 56 = 7 * 8 i.e 56 is a product
of two consecutive integers 7 and 8.

Input  : 8
Output : Not a Pronic Number
Explanation: 8 = 2 * 4 i.e 8 is a product of
2 and 4 which are not consecutive integers.```

## C++

 `// C/C++ program to check``// if a number is pronic``#include ``#include ``using` `namespace` `std;` `// function to check``// Pronic Number``bool` `checkPronic(``int` `x)``{` `    ``for` `(``int` `i = 0;``            ``i <= (``int``)(``sqrt``(x));``            ``i++)` `        ``// Checking Pronic Number``        ``// by multiplying consecutive``        ``// numbers``        ``if` `(x == i * (i + 1))``        ``return` `true``;` `    ``return` `false``;``}` `// Driver Code``int` `main(``void``)``{``    ``// Printing Pronic Numbers``    ``// upto 200``    ``for` `(``int` `i = 0; i <= 200; i++)``        ``if` `(checkPronic(i))``            ``cout << i << ``" "``;``    ` `    ``return` `0;``}` `// This code is contributed``// by Nikita Tiwari.`

## Java

 `// Java program to check and``// Print Pronic Number upto 200``import` `java.io.*;``import` `java.util.*;``import` `java.math.*;` `class` `GFG``{` `    ``// function to check Pronic Number``    ``static` `boolean` `checkPronic(``int` `x)``    ``{``        ``for` `(``int` `i = ``0``;``             ``i <= (``int``)(Math.sqrt(x));``             ``i++)``            ` `            ``// Checking Pronic Number``            ``// by multiplying consecutive``            ``// numbers``            ``if` `(x == i * (i + ``1``))``                ``return` `true``;``        ` `        ``return` `false``;``    ``}` `    ``// Driver Code``    ``public` `static` `void` `main(String[] args)``    ``{``        ``// Printing Pronic``        ``// Numbers upto 200``        ``for` `(``int` `i = ``0``; i <= ``200``; i++)``            ``if` `(checkPronic(i))``                ``System.out.print(i + ``" "``);    ``    ``}``}` `// This code is contributed``// by Nikita Tiwari`

## Python3

 `# Python program to check``# and print Pronic Numbers``# upto 200``import` `math` `# function to check``# Pronic Number``def` `checkPronic (x) :` `    ``i ``=` `0``    ``while` `( i <``=` `(``int``)(math.sqrt(x)) ) :``        ` `        ``# Checking Pronic Number``        ``# by multiplying consecutive``        ``# numbers``        ``if` `( x ``=``=` `i ``*` `(i ``+` `1``)) :``            ``return` `True``        ``i ``=` `i ``+` `1` `    ``return` `False` `# Driver Code` `# Printing Pronic``# Numbers upto 200``i ``=` `0``while` `(i <``=` `200` `) :``    ``if` `checkPronic(i) :``        ``print``(i,end``=``" "``)``    ``i ``=` `i ``+` `1` `# This code is contributed``# by Nikita Tiwari.`

## C#

 `// Java program to check and``// Print Pronic Number upto 200``using` `System;` `class` `GFG``{` `    ``// function to check``    ``// Pronic Number``    ``static` `bool` `checkPronic(``int` `x)``    ``{``        ``for` `(``int` `i = 0;``                 ``i <= (``int``)(Math.Sqrt(x));``                 ``i++)``            ` `            ``// Checking Pronic Number by``            ``// multiplying consecutive numbers``            ``if` `(x == i * (i + 1))``                ``return` `true``;``        ` `        ``return` `false``;``    ``}` `    ``// Driver Code``    ``public` `static` `void` `Main()``    ``{``        ``// Printing Pronic``        ``// Numbers upto 200``        ``for` `(``int` `i = 0; i <= 200; i++)``            ``if` `(checkPronic(i))``                ``Console.Write(i + ``" "``);``    ``}``}` `// This code is contributed by vt_m.`

## PHP

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## Javascript

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Output :

`0 2 6 12 20 30 42 56 72 90 110 132 156 182`

Time complexity: O( n sqrt n) to check for n numbers
Auxiliary Space : O(1)
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