Open In App

Java Program to Check if all array elements can be converted to pronic numbers by rotating digits

Improve
Improve
Like Article
Like
Save
Share
Report

Given an array arr[] of size N, the task is to check if it is possible to convert all of the array elements to a pronic number by rotating the digits of array elements any number of times.

Examples:

Input: {321, 402, 246, 299} 
Output: True 
Explanation: 
arr[0] ? Right rotation once modifies arr[0] to 132 (= 11 × 12). 
arr[1] ? Right rotation once modifies arr[0] to 240 (= 15 × 16). 
arr[2] ? Right rotation twice modifies arr[2] to 462 (= 21 × 22). 
arr[3] ? Right rotation twice modifies arr[3] to 992 (= 31 × 32).

Input: {433, 653, 402, 186}
Output: False

Approach: Follow the steps below to solve the problem:

  • Traverse the array and check for each array element, whether it is possible to convert it to a pronic number.
  • For each array element, apply all the possible rotations and check after each rotation, whether the generated number is pronic or not.
  • If it is not possible to convert any array element to a pronic number, print “False”.
  • Otherwise, print “True”.

Below is the implementation of the above approach:

Java




// Java program for the above approach
  
import java.io.*;
import java.lang.*;
import java.util.*;
  
class GFG {
  
  // function to check Pronic Number
  static boolean isPronic(int x)
  {
  
    for (int i = 0; i < (int)(Math.sqrt(x)) + 1; i++) {
  
      // Checking Pronic Number
      // by multiplying consecutive
      // numbers
      if (x == i * (i + 1)) {
        return true;
      }
    }
  
    return false;
  }
  
  // Function to check if any permutation
  // of val is a pronic number or not
  static boolean checkRot(int val)
  {
    String temp = Integer.toString(val);
    for (int i = 0; i < temp.length(); i++) 
    {
      if (isPronic(Integer.parseInt(temp)) == true) {
        return true;
      }
  
      temp = temp.substring(1) + temp.charAt(0);
    }
    return false;
  }
  
  // Function to check if all array
  // elements can be converted to
  // a pronic number or not
  static boolean check(int arr[], int N)
  {
  
    // Traverse the array
    for (int i = 0; i < N; i++) 
    {
  
      // If current element
      // cannot be converted
      // to a pronic number
      if (checkRot(arr[i]) == false
      {
        return false;
      }
    }
    return true;
  }
  
  // Driver code
  public static void main(String[] args)
  {
  
    // Given array
    int arr[] = { 321, 402, 246, 299 };
    int N = arr.length;
  
    // Function call
    System.out.println(
      (check(arr, N) ? "True" : "False"));
  }
}
  
// This code is contributed by Kingash.


Output: 

True

 

Time Complexity: O(N3/2)
Auxiliary Space: O(1)

Please refer complete article on Check if all array elements can be converted to pronic numbers by rotating digits for more details!



Last Updated : 27 Jan, 2022
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads