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# C# | Math.Abs() Method | Set – 2

• Last Updated : 01 Feb, 2019

C# | Math.Abs() Method | Set – 1

In C#, Abs() is a Math class method which is used to return the absolute value of a specified number. This method can be overload by passing the different type of parameters to it. There are total 7 methods in its overload list.

1. Math.Abs(Decimal)
2. Math.Abs(Double)
3. Math.Abs(Int16)
4. Math.Abs(Int32)
5. Math.Abs(Int64)
6. Math.Abs(SByte)
7. Math.Abs(Single)
8. #### Math.Abs(Int64)

This method is used to return the absolute value of a 64-bit signed integer.

Syntax:

`public static long Abs (long val);`

Parameter:

val: It is the required number which is greater than Int64.MinValue, but less than or equal to Int64.MaxValue of type System.Int64.

Return Type: It returns a 64-bit signed integer say r, such that 0 ≤ r ≤ Int64.MaxValue.

Exception: This method will give OverflowException if the value of val is equals to Int64.MinValue.

Example:

 `// C# Program to illustrate the``// Math.Abs(Int64) Method``using` `System;`` ` `class` `Geeks {`` ` `    ``// Main Method``    ``public` `static` `void` `Main()``    ``{`` ` `        ``// Taking long values``        ``long``[] val = {Int64.MaxValue, 78345482, -4687985, 0};`` ` `        ``// using foreach loop``        ``foreach``(``long` `value ``in` `val)`` ` `            ``// Displaying the result``            ``Console.WriteLine(``"Absolute value of {0} = {1}"``,``                                    ``value, Math.Abs(value));``    ``}``}`

Output:

```Absolute value of 9223372036854775807 = 9223372036854775807
Absolute value of 78345482 = 78345482
Absolute value of -4687985 = 4687985
Absolute value of 0 = 0
```

#### Math.Abs(SByte)

This method is used to return the absolute value of an 8-bit signed integer.

Syntax:

`public static sbyte Abs (sbyte val);`

Parameter:

val: It is the required number which is greater than SByte.MinValue, but less than or equal to SByte.MaxValue of type System.SByte.

Return Type: It returns a 8-bit signed integer say r, such that 0 ≤ r ≤ SByte.MaxValue.

Exception: This method will give OverflowException if the value of val is equals to SByte.MinValue.

Example:

 `// C# Program to illlustrate the``// Math.Abs(SByte) Method``using` `System;`` ` `class` `Geeks {`` ` `    ``// Main Method``    ``public` `static` `void` `Main()``    ``{`` ` `        ``// Taking SByte values``        ``sbyte``[] sb = {SByte.MaxValue, 45, -41, 0};`` ` `        ``// using foreach loop``        ``foreach``(``sbyte` `value ``in` `sb)`` ` `            ``// Displaying the result``            ``Console.WriteLine(``"Absolute value of {0} = {1}"``,``                                    ``value, Math.Abs(value));``    ``}``}`

Output:

```Absolute value of 127 = 127
Absolute value of 45 = 45
Absolute value of -41 = 41
Absolute value of 0 = 0
```

#### Math.Abs(Single)

This method is used to return the absolute value of a single-precision floating-point number.

Syntax:

`public static float Abs (float val);`

Parameter:

val: It is the required number which is greater than or equal to Single.MinValue, but less than or equal to MaxValue of type System.Single.

Return Type: It returns a single-precision floating-point number say r, such that 0 ≤ r ≤ Single.MaxValue.

Note:

• If val is equal to NegativeInfinity or PositiveInfinity, the return value will be PositiveInfinity.
• If the val is equal to NaN then return value will be NaN.

Example:

 `// C# Program to illlustrate the``// Math.Abs(Single) Method``using` `System;`` ` `class` `Geeks {`` ` `    ``// Main Method``    ``public` `static` `void` `Main()``    ``{`` ` `        ``float` `nan = ``float``.NaN;`` ` `        ``// Taking float values``        ``float``[] fl = {``float``.MinValue, 127.58f, 0.000f,``                    ``7556.48e10f, nan, ``float``.MaxValue};`` ` `        ``// using foreach loop``        ``foreach``(``float` `value ``in` `fl)`` ` `            ``// Displaying the result``            ``Console.WriteLine(``"Absolute value of {0} = {1}"``,``                                    ``value, Math.Abs(value));``    ``}``}`

Output:

```Absolute value of -3.402823E+38 = 3.402823E+38
Absolute value of 127.58 = 127.58
Absolute value of 0 = 0
Absolute value of 7.55648E+13 = 7.55648E+13
Absolute value of NaN = NaN
Absolute value of 3.402823E+38 = 3.402823E+38
```

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