C# | Math.Abs() Method | Set – 2

• Last Updated : 01 Feb, 2019

C# | Math.Abs() Method | Set – 1

In C#, Abs() is a Math class method which is used to return the absolute value of a specified number. This method can be overload by passing the different type of parameters to it. There are total 7 methods in its overload list.

1. Math.Abs(Decimal)
2. Math.Abs(Double)
3. Math.Abs(Int16)
4. Math.Abs(Int32)
5. Math.Abs(Int64)
6. Math.Abs(SByte)
7. Math.Abs(Single)
8. Math.Abs(Int64)

This method is used to return the absolute value of a 64-bit signed integer.

Syntax:

`public static long Abs (long val);`

Parameter:

val: It is the required number which is greater than Int64.MinValue, but less than or equal to Int64.MaxValue of type System.Int64.

Return Type: It returns a 64-bit signed integer say r, such that 0 ≤ r ≤ Int64.MaxValue.

Exception: This method will give OverflowException if the value of val is equals to Int64.MinValue.

Example:

 `// C# Program to illustrate the``// Math.Abs(Int64) Method``using` `System;`` ` `class` `Geeks {`` ` `    ``// Main Method``    ``public` `static` `void` `Main()``    ``{`` ` `        ``// Taking long values``        ``long``[] val = {Int64.MaxValue, 78345482, -4687985, 0};`` ` `        ``// using foreach loop``        ``foreach``(``long` `value ``in` `val)`` ` `            ``// Displaying the result``            ``Console.WriteLine(``"Absolute value of {0} = {1}"``,``                                    ``value, Math.Abs(value));``    ``}``}`

Output:

```Absolute value of 9223372036854775807 = 9223372036854775807
Absolute value of 78345482 = 78345482
Absolute value of -4687985 = 4687985
Absolute value of 0 = 0
```

Math.Abs(SByte)

This method is used to return the absolute value of an 8-bit signed integer.

Syntax:

`public static sbyte Abs (sbyte val);`

Parameter:

val: It is the required number which is greater than SByte.MinValue, but less than or equal to SByte.MaxValue of type System.SByte.

Return Type: It returns a 8-bit signed integer say r, such that 0 ≤ r ≤ SByte.MaxValue.

Exception: This method will give OverflowException if the value of val is equals to SByte.MinValue.

Example:

 `// C# Program to illlustrate the``// Math.Abs(SByte) Method``using` `System;`` ` `class` `Geeks {`` ` `    ``// Main Method``    ``public` `static` `void` `Main()``    ``{`` ` `        ``// Taking SByte values``        ``sbyte``[] sb = {SByte.MaxValue, 45, -41, 0};`` ` `        ``// using foreach loop``        ``foreach``(``sbyte` `value ``in` `sb)`` ` `            ``// Displaying the result``            ``Console.WriteLine(``"Absolute value of {0} = {1}"``,``                                    ``value, Math.Abs(value));``    ``}``}`

Output:

```Absolute value of 127 = 127
Absolute value of 45 = 45
Absolute value of -41 = 41
Absolute value of 0 = 0
```

Math.Abs(Single)

This method is used to return the absolute value of a single-precision floating-point number.

Syntax:

`public static float Abs (float val);`

Parameter:

val: It is the required number which is greater than or equal to Single.MinValue, but less than or equal to MaxValue of type System.Single.

Return Type: It returns a single-precision floating-point number say r, such that 0 ≤ r ≤ Single.MaxValue.

Note:

• If val is equal to NegativeInfinity or PositiveInfinity, the return value will be PositiveInfinity.
• If the val is equal to NaN then return value will be NaN.

Example:

 `// C# Program to illlustrate the``// Math.Abs(Single) Method``using` `System;`` ` `class` `Geeks {`` ` `    ``// Main Method``    ``public` `static` `void` `Main()``    ``{`` ` `        ``float` `nan = ``float``.NaN;`` ` `        ``// Taking float values``        ``float``[] fl = {``float``.MinValue, 127.58f, 0.000f,``                    ``7556.48e10f, nan, ``float``.MaxValue};`` ` `        ``// using foreach loop``        ``foreach``(``float` `value ``in` `fl)`` ` `            ``// Displaying the result``            ``Console.WriteLine(``"Absolute value of {0} = {1}"``,``                                    ``value, Math.Abs(value));``    ``}``}`

Output:

```Absolute value of -3.402823E+38 = 3.402823E+38
Absolute value of 127.58 = 127.58
Absolute value of 0 = 0
Absolute value of 7.55648E+13 = 7.55648E+13
Absolute value of NaN = NaN
Absolute value of 3.402823E+38 = 3.402823E+38
```

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