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BigInteger setBit() Method in Java
• Last Updated : 04 Dec, 2018

The java.math.BigInteger.setbit(index) method returns a Big-integer whose value is equivalent to this Big-integer with the designated bit set. The method computes (this | (1<<n)). The bit at index n of binary representation of Big-integer will be set means converted to 1.

Syntax:

`public BigInteger setbit(int n)`

Parameters: The method takes one parameter n which refers to the index of the bit that is needed to be set.

Return Value: The method returns the BigInteger value after setting the bit position n.

Exceptions: The method might throw an ArithmeticException when n is negative.

Examples:

```Input: value = 2300 index = 1
Output: 2302
Explanation:
Binary Representation of 2300 = 100011111100
bit at index 3 is 1 so set the bit at index 1
Now Binary Representation becomes 100011111110
and Decimal equivalent of 100011111110 is 2302

Input: value = 5482549 index = 1
Output: 5482551
```

Below program illustrate the setBit(index) method of BigInteger:

 `// Program to demonstrate setBit() method of BigInteger `` ` `import` `java.math.*;`` ` `public` `class` `GFG {`` ` `    ``public` `static` `void` `main(String[] args)``    ``{`` ` `        ``// Creating BigInteger object``        ``BigInteger biginteger = ``new` `BigInteger(``"2300"``);`` ` `        ``// Creating an integer i for index``        ``int` `i = ``1``;`` ` `        ``// Calling setBit() method on bigInteger at index i``        ``// store the return BigInteger``        ``BigInteger changedvalue = biginteger.setBit(i);`` ` `        ``String result = ``"After applying setBit at index "` `+ ``        ``i + ``" of "` `+ biginteger+ ``" New Value is "` `+ changedvalue;`` ` `        ``// Displaying the result``        ``System.out.println(result);``    ``}``}`
Output:
```After applying setBit at index 1 of 2300 New Value is 2302
```

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