BigInteger setBit() Method in Java
Last Updated :
03 Mar, 2022
The java.math.BigInteger.setbit(index) method returns a Big-integer whose value is equivalent to this Big-integer with the designated bit set. The method computes (this | (1<<n)). The bit at index n of binary representation of Big-integer will be set means converted to 1.
Syntax:
public BigInteger setbit(int n)
Parameters: The method takes one parameter n which refers to the index of the bit that is needed to be set.
Return Value: The method returns the BigInteger value after setting the bit position n.
Exceptions: The method might throw an ArithmeticException when n is negative..
Examples:
Input: value = 2300 index = 1
Output: 2302
Explanation:
Binary Representation of 2300 = 100011111100
bit at index 1 is 0 so set the bit at index 1
Now Binary Representation becomes 100011111110
and Decimal equivalent of 100011111110 is 2302
Input: value = 5482549 index = 1
Output: 5482551
Below program illustrate the setBit(index) method of BigInteger:
Java
import java.math.*;
public class GFG {
public static void main(String[] args)
{
BigInteger biginteger = new BigInteger(" 2300 ");
int i = 1 ;
BigInteger changedvalue = biginteger.setBit(i);
String result = "After applying setBit at index " +
i + " of " + biginteger+ " New Value is " + changedvalue;
System.out.println(result);
}
}
|
Output:
After applying setBit at index 1 of 2300 New Value is 2302
Reference: https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#setBit(int)
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