AbstractList get() method in Java with Examples
Last Updated :
26 Nov, 2018
The get() method of java.util.AbstractList class is used to return the element at the specified position in this list.
Syntax:
public abstract E get(int index)
Parameters: This method takes index of the element as a parameter, the element at which is to be returned.
Returns Value: This method returns the element at the specified position in this list.
Exception: This method throws IndexOutOfBoundsException if the index is out of range (index = size()).
Below are the examples to illustrate the get() method.
Example 1:
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
AbstractList<Integer>
arrlist1 = new ArrayList<Integer>();
arrlist1.add( 10 );
arrlist1.add( 20 );
arrlist1.add( 30 );
arrlist1.add( 40 );
arrlist1.add( 50 );
System.out.println( "ArrayListlist : "
+ arrlist1);
int value = arrlist1.get( 3 );
System.out.println( "Element at index 3 : "
+ value);
}
catch (IndexOutOfBoundsException e) {
System.out.println( "Exception thrown : " + e);
}
}
}
|
Output:
ArrayListlist : [10, 20, 30, 40, 50]
Element at index 3 : 40
Example 2:
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
AbstractList<Integer>
arrlist1 = new ArrayList<Integer>();
arrlist1.add( 10 );
arrlist1.add( 20 );
arrlist1.add( 30 );
arrlist1.add( 40 );
arrlist1.add( 50 );
System.out.println( "ArrayListlist : "
+ arrlist1);
System.out.println( "\nTrying to get "
+ "the element from out"
+ " of range index " );
int value = arrlist1.get( 7 );
System.out.println( "Element at index 7 : "
+ value);
}
catch (IndexOutOfBoundsException e) {
System.out.println( "Exception thrown : " + e);
}
}
}
|
Output:
ArrayListlist : [10, 20, 30, 40, 50]
Trying to get the element from out of range index
Exception thrown : java.lang.IndexOutOfBoundsException: Index: 7, Size: 5
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