AbstractList listIterator() Method in Java with Examples
The listIterator() method of java.util.AbstractList class is used to return a list-iterator containing the same elements as that of the AbstractList in proper and same sequence starting from a specific position or index number which is passed as a parameter to this method.
Syntax:
ListIterator new_list
= AbstractList.listIterator(int index);
Parameters: The parameter index is an integer type value that specifies the position of the element from where ListIterator starts operating and returning values.
Return Value: The method returns the list created using ListIterator, starting from the specified index.
Below program illustrate the AbstractList.listIterator() method:
Program 1:
import java.util.*;
public class LinkedListDemo {
public static void main(String args[])
{
AbstractList<String>
abs_list = new LinkedList<String>();
abs_list.add( "Geeks" );
abs_list.add( "for" );
abs_list.add( "Geeks" );
abs_list.add( "10" );
abs_list.add( "20" );
System.out.println( "AbstractList:" + abs_list);
ListIterator list_Iter = abs_list.listIterator( 2 );
System.out.println( "The list is as follows:" );
while (list_Iter.hasNext()) {
System.out.println(list_Iter.next());
}
}
}
|
Output:
AbstractList:[Geeks, for, Geeks, 10, 20]
The list is as follows:
Geeks
10
20
Program 2:
import java.util.*;
public class LinkedListDemo {
public static void main(String args[])
{
AbstractList<Integer>
abs_list = new LinkedList<Integer>();
abs_list.add( 10 );
abs_list.add( 20 );
abs_list.add( 30 );
abs_list.add( 40 );
abs_list.add( 50 );
System.out.println( "AbstractList:" + abs_list);
ListIterator list_Iter = abs_list.listIterator( 2 );
System.out.println( "The list is as follows:" );
while (list_Iter.hasNext()) {
System.out.println(list_Iter.next());
}
}
}
|
Output:
AbstractList:[10, 20, 30, 40, 50]
The list is as follows:
30
40
50
Last Updated :
26 Nov, 2018
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