Node.js URLSearchParams.get()
Last Updated :
14 Oct, 2021
In URLSearchParams interface, the get() method returns the first value of the input search parameter.
Syntax:
URLSearchParams.get(name)
Returns:The string will be returned if the name-value pair is found, else null will be returned.
Parameters:
name – Input the name of the parameter.
Example1: When input parameter is present
var URL = require( 'url' ).URL;
let params = new URLSearchParams(url.search.substring(1));
let name = params.get( "name" );
let age = parseInt(params.get( "age" ), 10);
console.log(name)
console.log(age)
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Output:
Deepak
20
Example2: When input parameter is not present
var URL = require( 'url' ).URL;
let params = new URLSearchParams(url.search.substring(1));
let address = params.get( "address" );
console.log(address)
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Output:
null
Supported Browsers:
- Google Chrome
- IE
- Edge
- Opera
- Apple Safari
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