numpy.isfortran() in Python
Last Updated :
29 Nov, 2018
numpy.isfortran(array) : This is a logical function that checks whether array is Fortran contiguous or not.
Order : [C-contiguous, F-contiguous, A-contiguous; optional]
C-contiguous order in memory(last index varies the fastest). C order means that operating row-rise on the array will be slightly quicker.
FORTRAN-contiguous order in memory (first index varies the fastest). F order means that column-wise operations will be faster.
‘A’ means to read / write the elements in Fortran-like index order if, array is Fortran contiguous in memory, C-like order otherwise.
Parameters :
array : [array_like]Input array
Return :
True, if array is Fortran; else False
Code 1 :
import numpy as np
in_array = np.array([[ 1 , 2 , 3 ], [ 4 , 5 , 6 ]], order = 'C' )
print ( "Input array : \n" , in_array)
exp2_values = np.exp2(in_array)
print ( "\nisfortran : " , np.isfortran(in_array))
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Output :
Input array :
[[1 2 3]
[4 5 6]]
isfortran : False
Code 2 :
import numpy as np
in_array = np.array([[ 1 , 2 , 3 ], [ 4 , 5 , 6 ]], order = 'F' )
print ( "Input array : \n" , in_array)
exp2_values = np.exp2(in_array)
print ( "\nisfortran : " , np.isfortran(in_array))
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Output :
Input array :
[[1 2 3]
[4 5 6]]
isfortran : True
References :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.isfortran.html#numpy.isfortran
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