Open In App

wxPython – IsSubMenu() function in wx.MenuItem

Last Updated : 09 Jun, 2020
Improve
Improve
Like Article
Like
Save
Share
Report

In this article we are going to learn about IsSubMenu() function associated with wx.MenuItem class of wxPython. IsSubMenu() function simply returns True if the item is a submenu and False if the item is not a submenu.
No parameters are required by IsSubMenu() function.

Syntax:

wx.MenuItem.IsSubMenu(self)

Parameters:

No parameters are required by IsSubMenu() function.

Return Type:

bool

Code Example:




import wx
  
  
class Example(wx.Frame):
  
    def __init__(self, *args, **kwargs):
        super(Example, self).__init__(*args, **kwargs)
  
        self.InitUI()
  
    def InitUI(self):
  
        menubar = wx.MenuBar()
  
        fileMenu = wx.Menu()
  
        sm = wx.Menu()
        sm.Append(wx.ID_ANY, 'Submenu item 1')
        sm.Append(wx.ID_ANY, 'Submenu item 2')
        sm.Append(wx.ID_ANY, 'Submenu item 3')
        item = wx.MenuItem(fileMenu, 1, '&Check\tCtrl + c', helpString ="Check Help")
        item.SetSubMenu(sm)
        fileMenu.AppendMenu(wx.ID_ANY, 'I&mport', sm)
          
        n = item.IsSubMenu()
        # if item is sub menu
        if(n == True):
            print("Item is SubMenu Item")
        else:
            print("Item is not a SubMenu Item")
        menubar.Append(fileMenu, '&File')
        self.SetMenuBar(menubar)
  
        self.SetSize((350, 250))
        self.SetTitle('Submenu')
        self.Centre()
  
  
  
  
def main():
  
    app = wx.App()
    ex = Example(None)
    ex.Show()
    app.MainLoop()
  
  
if __name__ == '__main__':
    main()


Output:

Item is SubMenu Item.

Output Window:



Like Article
Suggest improvement
Share your thoughts in the comments

Similar Reads