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time.Time.Month() Function in Golang With Examples
  • Last Updated : 19 Apr, 2020

In Go language, time packages supplies functionality for determining as well as viewing time. The Time.Month() function in Go language is used to find the month of the year as provided by t. Moreover, this function is defined under the time package. Here, you need to import the “time” package in order to use these functions.

Syntax:

func (t Time) Month() Month

Here, “t” is the stated time.

Return value: It returns the month of the year as provided by “t”.

Example 1:



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// Golang program to illustrate the usage of
// Time.Month() function
  
// Including main package
package main
  
// Importing fmt and time
import "fmt"
import "time"
  
// Calling main
func main() {
  
    // Declaring t in UTC
    t := time.Date(2019, 6, 5,
       11, 51, 04, 0, time.UTC)
  
    // Calling Month method
    month := t.Month()
  
    // Prints month as specified
    fmt.Printf("The stated month of the"+
      " year specified is: %v\n", month)
}

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Output:

The stated month of the year specified is: June

Example 2:

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// Golang program to illustrate the usage of
// Time.Month() function
  
// Including main package
package main
  
// Importing fmt and time
import "fmt"
import "time"
  
// Calling main
func main() {
  
    // Declaring t in UTC
    t := time.Date(2019, 23, 5,
        11, 51, 04, 0, time.UTC)
  
    // Calling Month method
    month := t.Month()
  
    // Prints month as specified
    fmt.Printf("The stated month of the "+
        "year specified is: %v\n", month)
}

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Output:

The stated month of the year specified is: November

Here, the month stated in the above code in an integer is out of usual range but it is normalized while conversion.




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