SQL query to find second highest salary?
Consider below simple table:
Name Salary --------------- abc 100000 bcd 1000000 efg 40000 ghi 500000
How to find the employee whose salary is second highest. For example, in above table, “ghi” has the second highest salary as 500000.
Below is simple query to find the employee whose salary is highest.
select *from employee where salary=(select Max(salary) from employee);
We can nest the above query to find the second largest salary.
select *from employee group by salary order by salary desc limit 1,1;
There are other ways :
SELECT name, MAX(salary) AS salary FROM employee WHERE salary IN (SELECT salary FROM employee MINUS SELECT MAX(salary) FROM employee);
SELECT name, MAX(salary) AS salary FROM employee WHERE salary <> (SELECT MAX(salary) FROM employee);
IN SQL Server using Common Table Expression or CTE, we can find the second highest salary:
WITH T AS ( SELECT * DENSE_RANK() OVER (ORDER BY Salary Desc) AS Rnk FROM Employees ) SELECT Name FROM T WHERE Rnk=2;
How to find the third largest salary?
Simple, we can do one more nesting.
SELECT name, MAX(salary) AS salary FROM employee WHERE salary < (SELECT MAX(salary) FROM employee WHERE salary < (SELECT MAX(salary) FROM employee) );
Note that instead of nesting for second, third, etc largest salary, we can find nth salary using general query like in MySQL:
SELECT salary FROM employee ORDER BY salary desc limit n-1,1
SELECT name, salary FROM employee A WHERE n-1 = (SELECT count(1) FROM employee B WHERE B.salary>A.salary)
If multiple employee have same salary.
Suppose you have to find 4th highest salary
SELECT * FROM employee WHERE salary= (SELECT DISTINCT(salary) FROM employee ORDER BY salary LIMIT 3,1);
Generic query will be
SELECT * FROM employee WHERE salary= (SELECT DISTINCT(salary) FROM employee ORDER BY salary LIMIT n-1,1);
This Solution is provided by Mohit.
This article is contributed by Kartik. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
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