# Sort 3 Integers without using if condition or using only max() function

Given three inteÂ­gers, print them in sorted order withÂ­out using if condition.
Examples :

```Input  : a = 3, b = 2, c = 9
Output : 2 3 9

Input  : a = 4, b = 1, c = 9
Output : 1 4 9```

Approach :
1. Find the maxÂ­iÂ­mum of a, b, c using max() function.
3. MulÂ­tiÂ­ply all inteÂ­gers by â€“1. Again find MinÂ­iÂ­mum of â€“a, â€“b, â€“c using max() function.
4. Add the Max and Min from above steps and subÂ­tract the sum from (a+b+c). It gives us midÂ­dle element.
It works for negative numbers also.

## C++

 `// C++ program to print three numbers  ``// in sorted order using max function ``#include ``using` `namespace` `std; `` ` `void` `printSorted(``int` `a, ``int` `b, ``int` `c) ``{ ``    ``// Find maximum element ``    ``int` `get_max = max(a, max(b, c)); `` ` `    ``// Find minimum element ``    ``int` `get_min = -max(-a, max(-b, -c)); `` ` `    ``int` `get_mid = (a + b + c) ``                 ``- (get_max + get_min); `` ` `    ``cout << get_min << ``" "` `<< get_mid ``        ``<< ``" "` `<< get_max; ``} `` ` `// Driver code ``int` `main() ``{ ``    ``int` `a = 4, b = 1, c = 9; ``    ``printSorted(a, b, c); ``    ``return` `0; ``} `

## Java

 `// Java program to print three numbers  ``// in sorted order using max function ``class` `GFG  ``{ ``     ` `    ``static` `void` `printSorted(``int` `a, ``int` `b, ``int` `c) ``    ``{ ``        ``// Find maximum element ``        ``int` `get_max = Math.max(a, Math.max(b, c)); ``     ` `        ``// Find minimum element ``        ``int` `get_min = -Math.max(-a, Math.max(-b, -c)); ``     ` `        ``int` `get_mid = (a + b + c)  ``                      ``- (get_max + get_min); ``     ` `        ``System.out.print(get_min + ``" "` `+ get_mid ``                                ``+ ``" "` `+ get_max); ``    ``} ``     ` `    ``// Driver code ``    ``public` `static` `void` `main(String[] args) ``    ``{ ``         ` `        ``int` `a = ``4``, b = ``1``, c = ``9``; ``         ` `        ``printSorted(a, b, c); ``    ``} ``} `` ` `// This code is contributed by Anant Agarwal. `

## Python3

 `# Python3 program to print three numbers  ``# in sorted order using max function `` ` `def` `printSorted(a, b, c): ``     ` `    ``# Find maximum element ``    ``get_max ``=` `max``(a, ``max``(b, c)) `` ` `    ``# Find minimum element ``    ``get_min ``=` `-``max``(``-``a, ``max``(``-``b, ``-``c)) `` ` `    ``get_mid ``=` `(a ``+` `b ``+` `c) ``-` `(get_max ``+` `get_min) `` ` `    ``print``(get_min, ``" "` `, get_mid, ``" "` `, get_max) `` ` `# Driver Code ``a, b, c ``=` `4``, ``1``, ``9``printSorted(a, b, c) `` ` `# This code is contributed by Anant Agarwal. `

## C#

 `// C# program to print three numbers  ``// in sorted order using max function ``using` `System; `` ` `class` `GFG { ``     ` `    ``static` `void` `printSorted(``int` `a, ``int` `b, ``int` `c) ``    ``{ ``        ``// Find maximum element ``        ``int` `get_max = Math.Max(a, Math.Max(b, c)); ``     ` `        ``// Find minimum element ``        ``int` `get_min = -Math.Max(-a, Math.Max(-b, -c)); ``     ` `        ``int` `get_mid = (a + b + c) - ``                      ``(get_max + get_min); ``     ` `    ``Console.Write(get_min + ``" "` `+ get_mid ``                          ``+ ``" "` `+ get_max); ``    ``} ``     ` `    ``// Driver code ``    ``public` `static` `void` `Main() ``    ``{ ``        ``int` `a = 4, b = 1, c = 9; ``         ` `        ``printSorted(a, b, c); ``    ``} ``} `` ` `// This code is contributed by nitin mittal. `

## PHP

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## Javascript

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Output:

` 1 4 9`

Time Complexity: O(1)
Auxiliary Space: O(1)

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