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Python – Summation of tuple dictionary values
• Last Updated : 17 Dec, 2019

Sometimes, while working with data, we can have a problem in which we need to find the summation of tuple elements that are received as values of dictionary. We may have a problem to get index wise summation. Let’s discuss certain ways in which this particular problem can be solved.

Method #1 : Using `tuple() + sum() + zip() + values()`
The combination of above methods can be used to perform this particular task. In this, we just zip together equi index values extracted by values() using zip(). Then find summation using respective function. Finally result is returned as index wise summation as a tuple.

 `# Python3 code to demonstrate working of``# Summation of tuple dictionary values``# Using tuple() + sum() + zip() + values()`` ` `# Initializing dictionary``test_dict ``=` `{``'gfg'` `: (``5``, ``6``, ``1``), ``'is'` `: (``8``, ``3``, ``2``), ``'best'` `: (``1``, ``4``, ``9``)}`` ` `# printing original dictionary``print``(``"The original dictionary is : "` `+` `str``(test_dict))`` ` `# Summation of tuple dictionary values``# Using tuple() + sum() + zip() + values()``res ``=` `tuple``(``sum``(x) ``for` `x ``in` `zip``(``*``test_dict.values()))`` ` `# printing result``print``(``"The summation from each index is : "` `+` `str``(res))`
Output :
```The original dictionary is : {'is': (8, 3, 2), 'best': (1, 4, 9), 'gfg': (5, 6, 1)}
The summation from each index is : (14, 13, 12)
```

Method #2 : Using `tuple() + map() + values()`
This is yet another way in which this task can be performed. The difference is that we use map() instead of loop.

 `# Python3 code to demonstrate working of``# Summation of tuple dictionary values``# Using tuple() + map() + values()`` ` `# Initializing dictionary``test_dict ``=` `{``'gfg'` `: (``5``, ``6``, ``1``), ``'is'` `: (``8``, ``3``, ``2``), ``'best'` `: (``1``, ``4``, ``9``)}`` ` `# printing original dictionary``print``(``"The original dictionary is : "` `+` `str``(test_dict))`` ` `# Summation of tuple dictionary values``# Using tuple() + map() + values()``temp ``=` `[]``for` `sub ``in` `test_dict.values():``    ``temp.append(``list``(sub))``res ``=` `tuple``(``map``(``sum``, temp))`` ` `# printing result``print``(``"The summation from each index is : "` `+` `str``(res))`
Output :
```The original dictionary is : {'is': (8, 3, 2), 'best': (1, 4, 9), 'gfg': (5, 6, 1)}
The summation from each index is : (14, 13, 12)
```

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