Sometimes, while programming, we have a problem in which we might need to perform certain bitwise operations among tuple list elements. This is an essential utility as we come across bitwise operations many times. Let’s discuss certain ways in which XOR can be performed.
Method #1 : Using reduce() + lambda + “^” operator + loop
The above functions can be combined to perform this task. We can first flatten the tuple list using loop and then employ reduce() to accumulate the result of XOR logic specified by the lambda function. Works only with Python2.
# Python code to demonstrate working of # Records list XOR# Using reduce() + lambda + "^" operator + loops # initializing list test_list = [(4, 6), (2, ), (3, 8, 9)] # printing original list print("The original list is : " + str(test_list)) # Records list XOR# Using reduce() + lambda + "^" operator + loopstemp = []for sub in test_list: for ele in sub: temp.append(ele)res = reduce(lambda x, y: x ^ y, temp) # printing result print("The Bitwise XOR of records list elements are : " + str(res)) |
The original list is : [(4, 6), (2, ), (3, 8, 9)] The Bitwise XOR of records list elements are : 2
Method #2 : Using reduce() + operator.ixor + chain()
This task can also be performed using this method. In this the task performed by lambda function in above method is performed using ior function for cumulative XOR operation, the flattening of elements to list is performed using chain(). Works with Python2 only.
# Python code to demonstrate working of # Records list XOR# Using reduce() + operator.ixor from operator import ixor from itertools import chain # initializing list test_list = [(4, 6), (2, ), (3, 8, 9)] # printing original list print("The original list is : " + str(test_list)) # Records list XOR# Using reduce() + operator.ixor temp = list(chain(*test_list))res = reduce(ixor, temp) # printing result print("The Bitwise XOR of records list elements are : " + str(res)) |
The original list is : [(4, 6), (2, ), (3, 8, 9)] The Bitwise XOR of records list elements are : 2
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