Python | Pandas TimedeltaIndex.difference
Last Updated :
21 Sep, 2021
Python is a great language for doing data analysis, primarily because of the fantastic ecosystem of data-centric python packages. Pandas is one of those packages and makes importing and analyzing data much easier.
Pandas TimedeltaIndex.difference() function return a new Index with elements from the index that are not in other. This is the set difference of two Index objects. It’s sorted if sorting is possible.
Syntax : TimedeltaIndex.difference(other)
Parameters :
other : Index or array-like
Return : difference : Index
Example #1: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.
Python3
import pandas as pd
tidx1 = pd.TimedeltaIndex(data = [ '06:05:01.000030' , '+23:59:59.999999' ,
'22 day 2 min 3us 10ns' , '+23:29:59.999999' ,
'+12:19:59.999999' ])
tidx2 = pd.TimedeltaIndex(data = [ '09:11:18.000030' , '+23:59:59.999999' ,
'9 day 18 min 3us ' , '+23:29:59.999999' ,
'+12:19:59.999999' ])
print (tidx1, "\n" , tidx2)
|
Output :
Now we will use the TimedeltaIndex.difference() function to find the set difference.
Output :
As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.
Example #2: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.
Python3
import pandas as pd
tidx1 = pd.TimedeltaIndex(start = '1 days 02:00:12.001124' , periods = 5 ,
freq = 'D' , name = 'Koala' )
tidx2 = pd.TimedeltaIndex(start = '3 days 02:00:12.001124' , periods = 5 ,
freq = 'D' , name = 'Koala' )
print (tidx1, "\n" , tidx2)
|
Output :
Now we will use the TimedeltaIndex.difference() function to find the set difference.
Output :
As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.
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