Python – Pairs with multiple similar values in dictionary
Sometimes, whilw working with dictionaries, we can have a problem in which we need to keep the dictionaries which are having similar key’s value in other dictionary. This is a very specific problem. This can have applications in web development domain. Lets discuss certain ways in which this task can be performed.
Method #1 : Using list comprehension
This task can be performed using list comprehension. In this we iterate each element in list and nesting loop is run to match key’s value with every other value.
# Python3 code to demonstrate # Pairs with multiple similar values in dictionary# using list comprehension # Initializing listtest_list = [{'Gfg' : 1, 'is' : 2}, {'Gfg' : 2, 'is' : 2}, {'Gfg' : 1, 'is' : 2}] # printing original listprint("The original list is : " + str(test_list)) # Pairs with multiple similar values in dictionary# using list comprehensionres = [sub for sub in test_list if len([ele for ele in test_list if ele['Gfg'] == sub['Gfg']]) > 1] # printing result print ("List after keeping dictionary with same key's value : " + str(res)) |
Output :
The original list is : [{'is': 2, 'Gfg': 1}, {'is': 2, 'Gfg': 2}, {'is': 2, 'Gfg': 1}]
List after keeping dictionary with same key's value : [{'is': 2, 'Gfg': 1}, {'is': 2, 'Gfg': 1}]
Method #2 : Using Counter() + list comprehension
In this method, the task of finding the frequency is performed using Counter() and then task of finding the elements having multiple keys value is done using list comprehension.
# Python3 code to demonstrate # Pairs with multiple similar values in dictionary# using list comprehension + Counter()from collections import Counter # Initializing listtest_list = [{'Gfg' : 1, 'is' : 2}, {'Gfg' : 2, 'is' : 2}, {'Gfg' : 1, 'is' : 2}] # printing original listprint("The original list is : " + str(test_list)) # Pairs with multiple similar values in dictionary# using list comprehension + Counter()temp = Counter(sub['Gfg'] for sub in test_list)res = [ele for ele in test_list if temp[ele['Gfg']] > 1] # printing result print ("List after keeping dictionary with same key's value : " + str(res)) |
Output :
The original list is : [{'is': 2, 'Gfg': 1}, {'is': 2, 'Gfg': 2}, {'is': 2, 'Gfg': 1}]
List after keeping dictionary with same key's value : [{'is': 2, 'Gfg': 1}, {'is': 2, 'Gfg': 1}]
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