Sometimes, we need to find the specific problem of getting the pair which yields the maximum remainder. In some case, we don’t with to change the ordering of list and perform some operation in the similar list without using extra space. Let’s discuss certain ways in which this can be performed.
Method #1 : Using list comprehension + max() + combination() + lambda
This particular task can be performed using the combination of above functions in which we use list comprehension to bind all the functionalities and max function to get the maximum modulo, combination function finds all remainders internally and lambda function is used to compute the modulo.
# Python3 code to demonstrate # Maximum modulo pair # using list comprehension + max() + combinations() + lambda from itertools import combinations # initializing list test_list = [3, 4, 1, 7, 9, 1] # printing original list print("The original list : " + str(test_list)) # using list comprehension + max() + combinations() + lambda # Maximum modulo pair res = max(combinations(test_list, 2), key = lambda sub: sub[0] % sub[1]) # print result print("The maximum remainder pair is : " + str(res)) |
The original list : [3, 4, 1, 7, 9, 1] The maximum remainder pair is : (7, 9)
Method #2 : Using list comprehension + nlargest() + combination() + lambda
This method has potential of not only finding a single maximum but also k maximum modulo pairs if required and uses nlargest function instead of max function to achieve this functionality.
# Python3 code to demonstrate # Maximum modulo pair # using list comprehension + nlargest() + combinations() + lambda from itertools import combinations from heapq import nlargest # initializing list test_list = [3, 4, 1, 7, 9, 8] # printing original list print("The original list : " + str(test_list)) # using list comprehension + max() + combinations() + lambda # Maximum modulo pair # computes 2 maximum pair remainders res = nlargest(2, combinations(test_list, 2), key = lambda sub: sub[0] % sub[1]) # print result print("The maximum remainder pair is : " + str(res)) |
The original list : [3, 4, 1, 7, 9, 8] The maximum remainder pair is : [(7, 9), (7, 8)]
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