# Python | Maximum and Minimum value from two lists

• Last Updated : 16 Aug, 2022

The problem of finding maximum and minimum values in a list is quite common. But sometimes this problem can be extended in two lists and hence becomes a modified problem. This article discusses shorthands by which this task can be performed easily. Let’s discuss certain ways in which this problem can be solved.

Method #1: Using max() + min() + “+” operator The maximum and minimum values can be determined by the conventional max and min function of python and the extension of one to two lists can be dealt using the “+” operator.

## Python3

 `# Python3 code to demonstrate``# maximum and minimum values in two lists``# using max() + min() + "+" operator` `# initializing lists``test_list1 ``=` `[``1``, ``3``, ``4``, ``5``, ``2``, ``6``]``test_list2 ``=` `[``3``, ``4``, ``8``, ``3``, ``10``, ``1``]` `# printing the original lists``print` `("The original ``list` `1` `is` `: " ``+` `str``(test_list1))``print` `("The original ``list` `2` `is` `: " ``+` `str``(test_list2))` `# using max() + min() + "+" operator``# maximum and minimum values in two lists``max_all ``=` `max``(test_list1 ``+` `test_list2)``min_all ``=` `min``(test_list1 ``+` `test_list2)` `# printing result``print` `("The maximum of both lists ``is` `: " ``+` `str``(max_all))``print` `("The minimum of both lists ``is` `: " ``+` `str``(min_all))`

Output:

```The original list 1 is : [1, 3, 4, 5, 2, 6]
The original list 2 is : [3, 4, 8, 3, 10, 1]
The maximum of both lists is : 10
The minimum of both lists is : 1```

Method #2: Using max() + min() + chain() Another method to perform this particular task is by using the chain function which performs the task similar to the “+” operator but using an iterator, hence faster.

## Python3

 `# Python3 code to demonstrate``# maximum and minimum values in two lists``# using max() + min() + "+" operator``from` `itertools ``import` `chain` `# initializing lists``test_list1 ``=` `[``1``, ``3``, ``4``, ``5``, ``2``, ``6``]``test_list2 ``=` `[``3``, ``4``, ``8``, ``3``, ``10``, ``1``]` `# printing the original lists``print` `("The original ``list` `1` `is` `: " ``+` `str``(test_list1))``print` `("The original ``list` `2` `is` `: " ``+` `str``(test_list2))` `# using max() + min() + "+" operator``# maximum and minimum values in two lists``max_all ``=` `max``(chain(test_list1, test_list2))``min_all ``=` `min``(chain(test_list1, test_list2))` `# printing result``print` `("The maximum of both lists ``is` `: " ``+` `str``(max_all))``print` `("The minimum of both lists ``is` `: " ``+` `str``(min_all))`

Output:

```The original list 1 is : [1, 3, 4, 5, 2, 6]
The original list 2 is : [3, 4, 8, 3, 10, 1]
The maximum of both lists is : 10
The minimum of both lists is : 1```

Method#3: Using list comprehension

## Python3

 `list1 ``=` `[``1``, ``3``, ``4``, ``5``, ``2``, ``6``];list2 ``=` `[``3``, ``4``, ``8``, ``3``, ``10``, ``1``]``x``=``[i ``for` `i ``in` `list1``+``list2]``print``(``"maximum element is "``,``max``(x),``"minimum element is "``,``min``(x))`

Output

`maximum element is  10 minimum element is  1`

## Python3

 `list1 ``=` `[``'1'``, ``'3'``, ``'4'``, ``'5'``, ``'2'``, ``'6'``];list2 ``=` `[``'3'``, ``'4'``, ``'8'``, ``'3'``, ``'10'``, ``'1'``]``x``=``[``int``(i) ``for` `a,i ``in` `enumerate``(list1``+``list2)]``print``(``"maximum element is "``,``max``(x),``"minimum element is "``,``min``(x))`

Output

`maximum element is  10 minimum element is  1`

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