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Python | Indices of sorted list of list elements

  • Last Updated : 11 May, 2020

Sorting is a common construct and there have been many variations of it being discussed. But sometimes, we need to perform the sorting on the list of list and moreover just require to find the order in which element occurs before getting sorted. Let’s find out how to get indices of sorted order in list of lists.

Method #1 : Using List comprehension + enumerate() + sort()

The combination of above 3 functions can be used to perform this particular task. In this, we perform the sorting taking triplets consisting of element and row and column coordinates and return them in 2nd step.




# Python3 code to demonstrate
# Indices of sorted list of list elements
# using List comprehension + enumerate() + sort()
  
# initializing list
test_list = [[4, 5, 1],
             [9, 3, 2],
             [8, 6]]
  
# printing original list
print("The original list : " + str(test_list))
  
# using List comprehension + enumerate() + sort()
# Indices of sorted list of list elements
res = [(i, j) for i, x in enumerate(test_list)
                     for j, k in enumerate(x)]
  
res.sort(key = lambda ij: test_list[ij[0]][ij[1]]) 
  
# print result
print("The indices of sorted order are : " + str(res))
Output :

The original list : [[4, 5, 1], [9, 3, 2], [8, 6]]
The indices of sorted order are : [(0, 2), (1, 2), (1, 1), (0, 0), (0, 1), (2, 1), (2, 0), (1, 0)]



 

Method #2 : Using sorted() + lambda

The task performed above can be performed as arguments to the sorted function and lambda function performs the task of list comprehension function as above.




# Python3 code to demonstrate
# Indices of sorted list of list elements
# using sorted() + lambda
  
# initializing list
test_list = [[4, 5, 1],
             [9, 3, 2],
             [8, 6]]
  
# printing original list
print("The original list : " + str(test_list))
  
# using sorted() + lambda
# Indices of sorted list of list elements
res = sorted([(i, j) for i, x in enumerate(test_list)
                            for j, k in enumerate(x)],
             key = lambda ij: test_list[ij[0]][ij[1]])
  
# print result
print("The indices of sorted order are : " + str(res))
Output :

The original list : [[4, 5, 1], [9, 3, 2], [8, 6]]
The indices of sorted order are : [(0, 2), (1, 2), (1, 1), (0, 0), (0, 1), (2, 1), (2, 0), (1, 0)]

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