# Python | Find the equivalent discount in successive discounts in percentages

You are given n successive discounts in percentages. Your task is to find the equivalent discount in percentage. Input will contain a list in which each element of the list will be discount in percentage that will be negative in sign. Examples:

```Input :  a = [-10, -35, -60, -75]
Output :  -94.14

Input :  a = [-5, -20, -10.-23]
Output :  -49.08```

SUCCESSIVE CHANGES = A + B + (A*B) / 100 How does this formula work? Let x be the initial value. After A% change, value of x becomes (x + x*A/100). After successive B% change, value of x becomes (x + x*A/100) + (x + x*A/100)*B/100. So increment in x’s value is x*(A + B + A*B/100)/100. In terms of percentage, we can say that the value is incremented by (A + B + A*B/100)% Approach:

• Simply, apply successive change formula between arr and arr and store the result in result variable.
• Now, calculate successive change between result and arr using the above formula and store the result in result variable and so on.

Code: Python program for finding the equivalent discount in successive discounts in percentages.

## Python3

 `# Function to find the equivalent discount in ` `# successive discounts in percentages` `def` `equivalentdis(a):` `    ``if``(``len``(a)``=``=` `1``):` `        ``return``(a[``0``])` `    ``else``:` `        ``# successive change from two = a + a+ (a*a)/100` `        ``change ``=``(a[``0``] ``+` `a[``1``]``+` `(a[``0``]``*``a[``1``])``/``100``)` `        ``for` `i ``in` `range``(``2``, ``len``(a)): ` `            ``# iterating a + a+ (a*a)/100 ` `            ``# len(a)-2 times` `            ``change ``=` `(change ``+` `a[i]``+``(change ``*` `a[i]) ``/` `100``)` `        ``return` `change; ` `# Driver code` `print``(equivalentdis([``-``10``, ``-``20``, ``-``30``, ``-``40``]))` ` `

Output :

`-69.75999999999999`

Time Complexity: O(n), where n is the size of a
Auxiliary Space: O(1), as no extra space is required

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