Python | Find mismatch item on same index in two list

Given two list of integers, the task is to find the index at which the element of two list doesn’t match.

Input:
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]

Output: [1, 3]
Explanation:
At index=1 we have 2 and 5 and at index=3
we have 4 and 6 which mismatches.

Below are some ways to achieve this task.

Method #1: Using Iteration

# Python code to find the index at which the  
# element of two list doesn't match. 
  
# List initialisation 
Input1 = [1, 2, 3, 4] 
Input2 = [1, 5, 3, 6] 
  
# Index initialisation 
y = 0
  
# Output list intialisation 
Output = []  
  
# Using iteration to find 
for x in Input1: 
    if x != Input2[y]: 
        Output.append(y) 
    y = y + 1
  
# Printing output 
print(Output) 

Output:

[1, 3]

Method #2: Using list Comprehension and zip

# Python code to find the index at which the  
# element of two list doesn't match. 
  
# List initialisation 
Input1 = [1, 2, 3, 4] 
Input2 = [1, 5, 3, 6] 
  
# Using list comprehension and zip  
Output = [Input2.index(y) for x, y in
       zip(Input1, Input2) if y != x] 
  
# Printing output 
print(Output) 

Output:

[1, 3]

Method #3: Using Enumerate

# Python code to find the index at which the  
# element of two list doesn't match. 
  
# List initialisation 
Input1 = [1, 2, 3, 4] 
Input2 = [1, 5, 3, 6] 
  
# Using list comprehension and enumerate 
Output = [index for index, elem in enumerate(Input2) 
                           if elem != Input1[index]] 
  
# Printing output 
print(Output) 

Output:

[1, 3]

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