Python | Find mismatch item on same index in two list

Given two list of integers, the task is to find the index at which the element of two list doesn’t match. 

Input:
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]

Output: [1, 3]
Explanation:
At index=1 we have 2 and 5 and at index=3
we have 4 and 6 which mismatches.

Below are some ways to achieve this task.
Method #1: Using Iteration 

Python3

# Python code to find the index at which the
# element of two list doesn't match.

# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]

# Index initialisation
y = 0

# Output list initialisation
Output = []

# Using iteration to find
for x in Input1:
    if x != Input2[y]:
        Output.append(y)
    y = y + 1

# Printing output
print(Output)

Output:

[1, 3]

Method #2: Using list Comprehension and zip 

Python3

# Python code to find the index at which the
# element of two list doesn't match.

# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]

# Using list comprehension and zip
Output = [Input2.index(y) for x, y in
       zip(Input1, Input2) if y != x]

# Printing output
print(Output)

Output:

[1, 3]

Method #3: Using Enumerate

Python3

# Python code to find the index at which the
# element of two list doesn't match.

# List initialisation
Input1 = [1, 2, 3, 4]
Input2 = [1, 5, 3, 6]

# Using list comprehension and enumerate
Output = [index for index, elem in enumerate(Input2)
                           if elem != Input1[index]]

# Printing output
print(Output)

Output:

[1, 3]