Python | Find mismatch item on same index in two list
Given two list of integers, the task is to find the index at which the element of two list doesn’t match.
Input: Input1 = [1, 2, 3, 4] Input2 = [1, 5, 3, 6] Output: [1, 3] Explanation: At index=1 we have 2 and 5 and at index=3 we have 4 and 6 which mismatches.
Below are some ways to achieve this task.
Method #1: Using Iteration
Python3
# Python code to find the index at which the# element of two list doesn't match.# List initialisationInput1 = [1, 2, 3, 4]Input2 = [1, 5, 3, 6]# Index initialisationy = 0# Output list initialisationOutput = []# Using iteration to findfor x in Input1: if x != Input2[y]: Output.append(y) y = y + 1# Printing outputprint(Output) |
Output:
[1, 3]
Method #2: Using list Comprehension and zip
Python3
# Python code to find the index at which the# element of two list doesn't match.# List initialisationInput1 = [1, 2, 3, 4]Input2 = [1, 5, 3, 6]# Using list comprehension and zipOutput = [Input2.index(y) for x, y in zip(Input1, Input2) if y != x]# Printing outputprint(Output) |
Output:
[1, 3]
Method #3: Using Enumerate
Python3
# Python code to find the index at which the# element of two list doesn't match.# List initialisationInput1 = [1, 2, 3, 4]Input2 = [1, 5, 3, 6]# Using list comprehension and enumerateOutput = [index for index, elem in enumerate(Input2) if elem != Input1[index]]# Printing outputprint(Output) |
Output:
[1, 3]
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