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Python | Find closest number to k in given list
• Last Updated : 17 Oct, 2019

Given a list of numbers and a variable K, where K is also a number, write a Python program to find the number in a list which is closest to the given number K.

Examples:

```Input : lst = [3.64, 5.2, 9.42, 9.35, 8.5, 8], K = 9.1
Output : 9.35

Input : lst = [9, 11, 5, 3, 25, 18], K = 6
Output : 5
```

Method #1 : Using `min()` method

In this approach, we use `min `method from Python and apply a key that finds the absolute difference of each element with K, and returns the element having minimum difference.

 `# Python3 program to find Closest number in a list`` ` `def` `closest(lst, K):``     ` `    ``return` `lst[``min``(``range``(``len``(lst)), key ``=` `lambda` `i: ``abs``(lst[i]``-``K))]``     ` `# Driver code``lst ``=` `[``3.64``, ``5.2``, ``9.42``, ``9.35``, ``8.5``, ``8``]``K ``=` `9.1``print``(closest(lst, K))`
Output:

```9.35
```

Method #2 : Using `numpy` module

This approach applies the same method but using numpy module. First we convert the given list to an array. Find absolute difference with K of each element, and return the minimum from it.

 `# Python3 program to find Closest number in a list``import` `numpy as np``def` `closest(lst, K):``     ` `     ``lst ``=` `np.asarray(lst)``     ``idx ``=` `(np.``abs``(lst ``-` `K)).argmin()``     ``return` `lst[idx]``     ` `# Driver code``lst ``=` `[``3.64``, ``5.2``, ``9.42``, ``9.35``, ``8.5``, ``8``]``K ``=` `9.1``print``(closest(lst, K))`
Output:
```9.35
```

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