Python – Filter unique valued tuples

Given a Tuple list, filter tuples that don’t contain duplicates.

Input : test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4, 9), (2, 3, 2)]
Output : [(3, 5, 6, 7)]
Explanation : Rest all tuples have duplicate values.

Input : test_list = [(3, 5, 6, 7, 7), (3, 2, 4, 3), (9, 4, 9), (2, 3, 2)]
Output : []
Explanation : All tuples have duplicate values.

Method #1 : Using loop + set()

In this, all the tuples are iterated, and duplicacy test is done using set(), if length of set is same as tuple, it does’nt contain duplicate.

Python3

# Python3 code to demonstrate working of
# Filter unique valued tuples
# Using loop + set()

# initializing list
test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]

# printing original list
print("The original list is : " + str(test_list))

res = []

for sub in test_list:

    # checking lengths to be equal
    if len(set(sub)) == len(sub):
        res.append(sub)

# printing results
print("Filtered tuples : " + str(res))

Output

The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]
Filtered tuples : [(3, 5, 6, 7), (9, 4)]

Method #2 : Using list comprehension

This performs similar task as above, difference being that this is one liner and compact.

Python3

# Python3 code to demonstrate working of
# Filter unique valued tuples
# Using list comprehension

# initializing list
test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]

# printing original list
print("The original list is : " + str(test_list))

# list comprehension used to filter
res = [sub for sub in test_list if len(set(sub)) == len(sub)]

# printing results
print("Filtered tuples : " + str(res))

Output

The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]
Filtered tuples : [(3, 5, 6, 7), (9, 4)]