Given a Tuple list, filter tuples that don’t contain duplicates.
Input : test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4, 9), (2, 3, 2)]
Output : [(3, 5, 6, 7)]
Explanation : Rest all tuples have duplicate values.Input : test_list = [(3, 5, 6, 7, 7), (3, 2, 4, 3), (9, 4, 9), (2, 3, 2)]
Output : []
Explanation : All tuples have duplicate values.
Method #1 : Using loop + set()
In this, all the tuples are iterated, and duplicacy test is done using set(), if length of set is same as tuple, it does’nt contain duplicate.
Python3
# Python3 code to demonstrate working of # Filter unique valued tuples# Using loop + set() # initializing listtest_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)] # printing original listprint("The original list is : " + str(test_list)) res = [] for sub in test_list: # checking lengths to be equal if len(set(sub)) == len(sub): res.append(sub) # printing resultsprint("Filtered tuples : " + str(res)) |
The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)] Filtered tuples : [(3, 5, 6, 7), (9, 4)]
Method #2 : Using list comprehension
This performs similar task as above, difference being that this is one liner and compact.
Python3
# Python3 code to demonstrate working of # Filter unique valued tuples# Using list comprehension # initializing listtest_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)] # printing original listprint("The original list is : " + str(test_list)) # list comprehension used to filterres = [sub for sub in test_list if len(set(sub)) == len(sub)] # printing resultsprint("Filtered tuples : " + str(res)) |
The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)] Filtered tuples : [(3, 5, 6, 7), (9, 4)]
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