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Python – Filter unique valued tuples
  • Last Updated : 02 Sep, 2020

Given a Tuple list, filter tuples that don’t contain duplicates.

Input : test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4, 9), (2, 3, 2)]
Output : [(3, 5, 6, 7)]
Explanation : Rest all tuples have duplicate values.

Input : test_list = [(3, 5, 6, 7, 7), (3, 2, 4, 3), (9, 4, 9), (2, 3, 2)]
Output : []
Explanation : All tuples have duplicate values.

Method #1 : Using loop + set()

In this, all the tuples are iterated, and duplicacy test is done using set(), if length of set is same as tuple, it does’nt contain duplicate.



Python3




# Python3 code to demonstrate working of 
# Filter unique valued tuples
# Using loop + set()
  
# initializing list
test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]
  
# printing original list
print("The original list is : " + str(test_list))
  
res = []
  
for sub in test_list:
      
    # checking lengths to be equal
    if len(set(sub)) == len(sub):
        res.append(sub)
          
# printing results
print("Filtered tuples : " + str(res))
Output
The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]
Filtered tuples : [(3, 5, 6, 7), (9, 4)]

Method #2 : Using list comprehension

This performs similar task as above, difference being that this is one liner and compact.

Python3




# Python3 code to demonstrate working of 
# Filter unique valued tuples
# Using list comprehension
  
# initializing list
test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]
  
# printing original list
print("The original list is : " + str(test_list))
  
# list comprehension used to filter
res = [sub for sub in test_list if len(set(sub)) == len(sub)]
          
# printing results
print("Filtered tuples : " + str(res))
Output
The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)]
Filtered tuples : [(3, 5, 6, 7), (9, 4)]

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