Sometimes, while working with records, we can have a problem in which we have to filter all the tuples from a list of tuples, which contains atleast one element from a list. This can have application in many domains working with data. Let’s discuss certain ways in which this task can be performed.
Method #1 : Using list comprehension
Using list comprehension is brute force method to perform this task in a shorthand. In this, we just check for each tuple and check if it contains any element from the target list.
# Python3 code to demonstrate working of # Filter tuples according to list element presence # using list comprehension # initialize list of tuple test_list = [(1, 4, 6), (5, 8), (2, 9), (1, 10)] # initialize target list tar_list = [6, 10] # printing original tuples list print("The original list : " + str(test_list)) # Filter tuples according to list element presence # using list comprehension res = [tup for tup in test_list if any(i in tup for i in tar_list)] # printing result print("Filtered tuple from list are : " + str(res)) |
The original list : [(1, 4, 6), (5, 8), (2, 9), (1, 10)] Filtered tuple from list are : [(1, 4, 6), (1, 10)]
Method #2 : Using set() + list comprehension
Above approach can be optimized by converting the containers to a set() reducing duplicates and performing a & operation to fetch the desired records.
# Python3 code to demonstrate working of # Filter tuples according to list element presence # using set() + list comprehension # initialize list of tuple test_list = [(1, 4, 6), (5, 8), (2, 9), (1, 10)] # initialize target list tar_list = [6, 10] # printing original tuples list print("The original list : " + str(test_list)) # Filter tuples according to list element presence # using set() + list comprehension res = [tup for tup in test_list if (set(tar_list) & set(tup))] # printing result print("Filtered tuple from list are : " + str(res)) |
The original list : [(1, 4, 6), (5, 8), (2, 9), (1, 10)] Filtered tuple from list are : [(1, 4, 6), (1, 10)]
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