Python – Convert dictionary to K sized dictionaries
Given a Dictionary, divide dictionary into K sized different dictionaries list.
Input : test_dict = {‘Gfg’ : 1, ‘is’ : 2, ‘best’ : 3, ‘for’ : 4, ‘geeks’ : 5, ‘CS’ : 6}, K = 3
Output : [{‘Gfg’: 1, ‘is’: 2, ‘best’: 3}, {‘for’: 4, ‘geeks’: 5, ‘CS’: 6}]
Explanation : Divided into size of 3 keys.Input : test_dict = {‘Gfg’ : 1, ‘is’ : 2, ‘best’ : 3, ‘for’ : 4}, K = 2
Output : [{‘Gfg’: 1, ‘is’: 2}, {‘best’: 3, ‘for’: 4}]
Explanation : Divided into size of 2 keys.
Method : Using loop
In this, we iterate for all the keys in dictionary using loop and bifurcate according to size and append to new list.
Python3
# Python3 code to demonstrate working of # Convert dictionary to K Keys dictionaries# Using loop # initializing dictionarytest_dict = {'Gfg' : 1, 'is' : 2, 'best' : 3, 'for' : 4, 'geeks' : 5, 'CS' : 6} # printing original dictionaryprint("The original dictionary is : " + str(test_dict)) # initializing K K = 2 res = []count = 0flag = 0indict = dict()for key in test_dict: indict[key] = test_dict[key] count += 1 # checking for K size and avoiding empty dict using flag if count % K == 0 and flag: res.append(indict) # reinitializing dictionary indict = dict() count = 0 flag = 1 # printing result print("The converted list : " + str(res)) |
Output
The original dictionary is : {'Gfg': 1, 'is': 2, 'best': 3, 'for': 4, 'geeks': 5, 'CS': 6}
The converted list : [{'Gfg': 1, 'is': 2}, {'best': 3, 'for': 4}, {'geeks': 5, 'CS': 6}]
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