Python | Combining tuples in list of tuples

Last Updated : 13 May, 2019

Sometimes, we might have to perform certain problems related to tuples in which we need to segregate the tuple elements to combine with the each element of complex tuple element( such as list ). This can have application in situations we need to combine values to form a whole. Let’s discuss certain ways in which this can be performed.

Method #1 : Using list comprehension
We can solve this particular problem using the list comprehension technique in which we can iterate for each tuple list and join it with other tuple attribute to join.

# Python3 code to demonstrate
# Combining tuples in list of tuples
# Using list comprehension
  
# initializing list
test_list = [([1, 2, 3], 'gfg'), ([5, 4, 3], 'cs')]
  
# printing original list
print("The original list : " + str(test_list))
  
# Using list comprehension
# Combining tuples in list of tuples
res = [ (tup1, tup2) for i, tup2 in test_list for tup1 in i ]
  
# print result
print("The list tuple combination : " + str(res))

Output :

The original list : [([1, 2, 3], ‘gfg’), ([5, 4, 3], ‘cs’)]
The list tuple combination : [(1, ‘gfg’), (2, ‘gfg’), (3, ‘gfg’), (5, ‘cs’), (4, ‘cs’), (3, ‘cs’)]

Method #2 : Using product() + list comprehension
Apart from using the tuple for generation of tuples, the product function can be used to get Cartesian product of list elements with tuple element, using the iterator internally.

# Python3 code to demonstrate
# Combining tuples in list of tuples
# Using product() + list comprehension
from itertools import product
  
# initializing list
test_list = [([1, 2, 3], 'gfg'), ([5, 4, 3], 'cs')]
  
# printing original list
print("The original list : " + str(test_list))
  
# Using product() + list comprehension
# Combining tuples in list of tuples
res = [ele for i, j in test_list for ele in product(i, [j])]
  
# print result
print("The list tuple combination : " + str(res))

Output :

The original list : [([1, 2, 3], ‘gfg’), ([5, 4, 3], ‘cs’)]
The list tuple combination : [(1, ‘gfg’), (2, ‘gfg’), (3, ‘gfg’), (5, ‘cs’), (4, ‘cs’), (3, ‘cs’)]

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