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PYGLET – Loading Program Resource

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  • Last Updated : 05 Aug, 2021
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In this article we will see how we can load a program resource in PYGLET module in python. Pyglet is easy to use but powerful library for developing visually rich GUI applications like games, multimedia etc. A window is a “heavyweight” object occupying operating system resources. Windows may appear as floating regions or can be set to fill an entire screen (fullscreen). In order to load a file i.e resource we use resource module of pyglet. This module allows applications to specify a search path for resources. Relative paths are taken to be relative to the application’s __main__ module. ZIP files can appear on the path; they will be searched inside. Loader load program resource files from disk. The loader contains a search path which can include filesystem directories, ZIP archives and Python packages.
We can create a window object with the help of command given below 
 

# creating a window
window = pyglet.window.Window(width, height, title)

 

In order to create window we use Loader method with the pyglet.resource
Syntax : resource.Loader(path)
Argument : It takes resource path i.e string as argument
Return : It returns Loader object 
 

Below is the implementation 
 

Python3




# importing pyglet module
import pyglet
import pyglet.window.key as key
   
# width of window
width = 500
   
# height of window
height = 500
   
# caption i.e title of the window
title = "Geeksforgeeks"
   
# creating a window
window = pyglet.window.Window(width, height, title)
   
# text 
text = "Welcome to GeeksforGeeks"
  
# creating label with following properties
# font = cooper
# position = 250, 150
# anchor position = center
label = pyglet.text.Label(text,
                          font_name ='Cooper',
                          font_size = 16,
                          x = 250
                          y = 150,
                          anchor_x ='center'
                          anchor_y ='center')
 
 
# creating a batch
batch = pyglet.graphics.Batch()
 
# loading geeksforgeeks image
image = pyglet.image.load('gfg.png')
 
 
# creating sprite object
# it is instance of an image displayed on-screen
sprite = pyglet.sprite.Sprite(image, x = 200, y = 230)
   
# on draw event
@window.event
def on_draw():
       
    # clear the window
    window.clear()
       
    # draw the label
    label.draw()
     
    # draw the image on screen
    sprite.draw()
       
# key press event    
@window.event
def on_key_press(symbol, modifier):
   
    # key "C" get press
    if symbol == key.C:
         
        # printing the message
        print("Key : C is pressed")
         
# image for icon
img = image = pyglet.resource.image("gfg.png")
 
# setting image as icon
window.set_icon(img)
 
# loading a file i.e program resource
value = pyglet.resource.Loader("E:/btech / certi / gfg.jpg")
 
# showing value with the help of label
label.text = str(value)
    
# start running the application
pyglet.app.run()

Output :
 

 


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