Program to find Nth term of series 0, 9, 22, 39, 60, 85, 114, 147, …..
Last Updated :
20 Aug, 2022
Given a number N. The task is to write a program to find the Nth term of the below series:
0, 9, 22, 39, 60, 85, 114, 147…..(N Terms)
Examples:
Input: N = 4
Output: 39
For N = 4
4th Term = ( 2 * 4 * 4 + 3 * 4 - 5)
= 39
Input: N = 10
Output: 224
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
#include <iostream>
#include <math.h>
using namespace std;
int nthTerm( int n)
{
return 2 * pow (n, 2) + 3 * n - 5;
}
int main()
{
int N = 4;
cout << nthTerm(N) << endl;
return 0;
}
|
Java
public class GFG {
static int nthTerm( int n)
{
return 2 * ( int )Math.pow(n, 2 ) + 3 * n - 5 ;
}
public static void main(String args[])
{
int N = 4 ;
System.out.println(nthTerm(N));
}
}
|
Python3
def nthTerm(n):
return 2 * pow (n, 2 ) + 3 * n - 5
N = 4
print (nthTerm(N))
|
C#
using System;
class GFG
{
static int nthTerm( int n)
{
return 2 * ( int )Math.Pow(n, 2) +
3 * n - 5;
}
public static void Main()
{
int N = 4;
Console.WriteLine(nthTerm(N));
}
}
|
PHP
<?php
function nthTerm( $n )
{
return 2 * pow( $n , 2) +
3 * $n - 5;
}
$N = 4;
echo nthTerm( $N ). "\n" ;
?>
|
Javascript
<script>
function nthTerm( n)
{
return 2 * Math.pow(n, 2) + 3 * n - 5;
}
let N = 4;
document.write(nthTerm(N));
</script>
|
Time Complexity: O(1), since there is no loop or recursion.
Space Complexity: O(1) since using constant variables
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