# Program to find the sum of a Series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n

You have been given a series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n, find out the sum of the series till nth term.
Examples:

```Input : n = 3
Output : 1.28704
Explanation : 1 + 1/2^2 + 1/3^3

Input : n = 5
Output : 1.29126
Explanation : 1 + 1/2^2 + 1/3^3 + 1/4^4 + 1/5^5
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

We use use power function to compute power.

## C/C++

 `// C program to calculate the following series ` `#include ` `#include ` ` `  `// Function to calculate the following series ` `double` `Series(``int` `n) ` `{ ` `    ``int` `i; ` `    ``double` `sums = 0.0, ser; ` `    ``for` `(i = 1; i <= n; ++i) { ` `        ``ser = 1 / ``pow``(i, i); ` `        ``sums += ser; ` `    ``} ` `    ``return` `sums; ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `n = 3; ` `    ``double` `res = Series(n); ` `    ``printf``(``"%.5f"``, res); ` `    ``return` `0; ` `} `

## Java

 `// Java program to calculate the following series ` `import` `java.io.*; ` ` `  `class` `Maths { ` ` `  `    ``// Function to calculate the following series ` `    ``static` `double` `Series(``int` `n) ` `    ``{ ` `        ``int` `i; ` `        ``double` `sums = ``0.0``, ser; ` `        ``for` `(i = ``1``; i <= n; ++i) { ` `            ``ser = ``1` `/ Math.pow(i, i); ` `            ``sums += ser; ` `        ``} ` `        ``return` `sums; ` `    ``} ` ` `  `    ``// Driver Code ` `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``int` `n = ``3``; ` `        ``double` `res = Series(n); ` `        ``res = Math.round(res * ``100000.0``) / ``100000.0``; ` `        ``System.out.println(res); ` `    ``} ` `} `

## Python

 `# Python program to calculate the following series ` `def` `Series(n): ` `    ``sums ``=` `0.0` `    ``for` `i ``in` `range``(``1``, n ``+` `1``): ` `        ``ser ``=` `1` `/` `(i``*``*``i) ` `        ``sums ``+``=` `ser ` `    ``return` `sums ` ` `  `# Driver Code ` `n ``=` `3` `res ``=` `round``(Series(n), ``5``) ` `print``(res) `

## C#

 `// C# program to calculate the following series ` `using System; ` ` `  `class Maths { ` ` `  `    ``// Function to calculate the following series ` `    ``static double Series(int n) ` `    ``{ ` `        ``int i; ` `        ``double sums = 0.0, ser; ` `        ``for (i = 1; i <= n; ++i) { ` `            ``ser = 1 / Math.Pow(i, i); ` `            ``sums += ser; ` `        ``} ` `        ``return sums; ` `    ``} ` ` `  `    ``// Driver Code ` `    ``public static void Main() ` `    ``{ ` `        ``int n = 3; ` `        ``double res = Series(n); ` `        ``res = Math.Round(res * 100000.0) / 100000.0; ` `        ``Console.Write(res); ` `    ``} ` `} ` `/*This code is contributed by vt_m.*/ `

## PHP

 ` `

output:

```1.28704
```

Output:

```1.28704
```

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Improved By : vt_m

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