Program to find the sum of a Series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n
You have been given a series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n, find out the sum of the series till nth term.
Examples:
Input : n = 3
Output : 1.28704
Explanation : 1 + 1/2^2 + 1/3^3
Input : n = 5
Output : 1.29126
Explanation : 1 + 1/2^2 + 1/3^3 + 1/4^4 + 1/5^5
We use power function to compute power.
C++
// C++ program to calculate the following series#include <bits/stdc++.h>using namespace std;// Function to calculate the following seriesdouble Series(int n){ int i; double sums = 0.0, ser; for(i = 1; i <= n; ++i) { ser = 1 / pow(i, i); sums += ser; } return sums;} // Driver Codeint main(){ int n = 3; double res = Series(n); cout << res; return 0;}// This code is contributed by Ankita saini |
C
// C program to calculate the following series#include <math.h>#include <stdio.h> // Function to calculate the following seriesdouble Series(int n){ int i; double sums = 0.0, ser; for (i = 1; i <= n; ++i) { ser = 1 / pow(i, i); sums += ser; } return sums;} // Driver Codeint main(){ int n = 3; double res = Series(n); printf("%.5f", res); return 0;} |
Java
// Java program to calculate the following seriesimport java.io.*; class Maths { // Function to calculate the following series static double Series(int n) { int i; double sums = 0.0, ser; for (i = 1; i <= n; ++i) { ser = 1 / Math.pow(i, i); sums += ser; } return sums; } // Driver Code public static void main(String[] args) { int n = 3; double res = Series(n); res = Math.round(res * 100000.0) / 100000.0; System.out.println(res); }} |
Python3
# Python program to calculate the following seriesdef Series(n): sums = 0.0 for i in range(1, n + 1): ser = 1 / (i**i) sums += ser return sums # Driver Coden = 3res = round(Series(n), 5)print(res) |
C#
// C# program to calculate the following seriesusing System; class Maths { // Function to calculate the following series static double Series(int n) { int i; double sums = 0.0, ser; for (i = 1; i <= n; ++i) { ser = 1 / Math.Pow(i, i); sums += ser; } return sums; } // Driver Code public static void Main() { int n = 3; double res = Series(n); res = Math.Round(res * 100000.0) / 100000.0; Console.Write(res); }}/*This code is contributed by vt_m.*/ |
PHP
<?php// PHP program to calculate// the following series // Function to calculate// the following seriesfunction Series($n){ $i; $sums = 0.0; $ser; for ($i = 1; $i <= $n; ++$i) { $ser = 1 / pow($i, $i); $sums += $ser; } return $sums;} // Driver Code $n = 3; $res = Series($n); echo $res; // This code is contributed by Vishal Tripathi.?> |
Javascript
<script>// Javascript program to calculate// the following seriesfunction Series(n){ let sums = 0.0; for(let i = 1; i < n + 1; i++) { ser = 1 / Math.pow(i, i); sums += ser; } return sums;}// Driver Codelet n = 3;let res = Math.round(Series(n) * 100000) / 100000;document.write(res);// This code is contributed by rohitsingh07052</script> |
Output:
1.28704
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