Bash shell script to find sum of digits

Given a number Num, find the sum of digits of the number.

Examples:

Input : 
444
Output :
sum of digits of 444 is : 12

Input :
34
Output :
sum of digits of 34 is : 7

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

1. Divide the number into single digits
2. Find the sum of digits .

Bash

# !/bin/bash 
  
# Program to find sum 
# of digits 
  
# Static input of the 
# number 
Num=123 
g=$Num 
  
# store the sum of  
# digits 
s=0 
  
# use while loop to 
# caclulate the sum 
# of all digits 
while [ $Num -gt 0 ] 
do
    # get Remainder 
    k=$(( $Num % 10 ))  
  
    # get next digit 
    Num=$(( $Num / 10 )) 
  
    # calculate sum of 
    # digit   
    s=$(( $s + $k ))  
done
echo  "sum of digits of $g is : $s"

Output

sum of digits of 123 is : 6

My Personal Notes

Recommended Posts:

Manish_100

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