Bash shell script to find sum of digits
Given a number Num, find the sum of digits of the number.
Examples:
Input : 444 Output : sum of digits of 444 is : 12 Input : 34 Output : sum of digits of 34 is : 7
Approach:
1. Divide the number into single digits 2. Find the sum of digits .
Bash
# !/bin/bash # Program to find sum # of digits # Static input of the # number Num=123 g=$Num # store the sum of # digits s=0 # use while loop to # caclulate the sum # of all digits while [ $Num -gt 0 ] do # get Remainder k=$(( $Num % 10 )) # get next digit Num=$(( $Num / 10 )) # calculate sum of # digit s=$(( $s + $k )) doneecho "sum of digits of $g is : $s" |
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Output
sum of digits of 123 is : 6
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