PHP | Imagick valid() Function
Last Updated :
23 Dec, 2019
The Imagick::valid() function is an inbuilt function in PHP which is used to check if the current item is valid.
Syntax:
bool Imagick::valid( void )
Parameters: This function doesn’t accept any parameter.
Return Value: This function returns TRUE on success.
Exceptions: This function throws ImagickException on error.
Below given programs illustrate the Imagick::valid() function in PHP:
Program 1:
<?php
try {
$imagick = new Imagick( 'undefined_source' );
if ( $imagick ->valid()) {
echo 'Image is valid' ;
}
} catch (exception $e ) {
echo 'Image is not valid' ;
}
?>
|
Output:
Image is not valid
Program 2:
<?php
try {
$imagick = new Imagick(
if ( $imagick ->valid()) {
echo 'Image is valid' ;
}
} catch (exception $e ) {
echo 'Image is not valid' ;
}
?>
|
Output:
Image is valid
Reference: https://www.php.net/manual/en/imagick.valid.php
Share your thoughts in the comments
Please Login to comment...