# Most frequent factor in a range of integers

You are given a range of numbers, from lower number to higher number (both inclusive). Consider all the factors of these numbers except 1, the task is to find the factor which appears the maximum number of times. If more than one number have maximum frequency than print anyone of them.

**Examples:**

Input :lower=10 higher=14Output :The factor with maximum frequency is 2.Input :lower=11 higher=11Output :The factor with maximum frequency is 11.

**Explanation: **

If we have a range of numbers, say 10 to 14. Then the factors other than 1 will be:

In the above case, frequency(2)= 3, which is maximum on comparing with other factors.

**Approach:**

1. If lower = higher, then all factors will have frequency 1. So we can print any number which is factor, since every number is a factor of itself so we print the same number.

2. Otherwise, we print ‘2’ as it will always be true for a range of numbers.

## C++

`// CPP program to find most common factor ` `// in a range. ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `int` `mostCommon(` `int` `lower, ` `int` `higher) ` `{ ` ` ` `// Check whether lower number ` ` ` `// and higher number are same ` ` ` `if` `(lower == higher) ` ` ` `return` `lower; ` ` ` `else` ` ` `return` `2; ` `} ` ` ` `// Driver Code ` `int` `main() ` `{ ` ` ` `int` `lower = 10; ` `// Lower number ` ` ` `int` `higher = 20; ` `// Higher number ` ` ` ` ` `printf` `(` `"The most frequent factor %d\n"` `, ` ` ` `mostCommon(lower, higher)); ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program to find most common factor ` `// in a range. ` ` ` `public` `class` `GfG { ` ` ` ` ` `public` `static` `int` `mostCommon(` `int` `lower, ` `int` `higher) ` ` ` `{ ` ` ` `// Check whether lower number ` ` ` `// and higher number are same ` ` ` `if` `(lower == higher) ` ` ` `return` `lower; ` ` ` `else` ` ` `return` `2` `; ` ` ` `} ` ` ` ` ` `// Driver code ` ` ` `public` `static` `void` `main(String []args) { ` ` ` ` ` `int` `lower = ` `10` `; ` `// Lower number ` ` ` `int` `higher = ` `20` `; ` `// Higher number ` ` ` `System.out.println(` `"The most frequent factor "` `+ ` ` ` `mostCommon(lower, higher)); ` ` ` `} ` `} ` ` ` `// This code is contributed by Rituraj Jain ` |

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## Python 3

`# Python 3 program to find most ` `# common factor in a range. ` `def` `mostCommon( lower, higher): ` ` ` ` ` `# Check whether lower number ` ` ` `# and higher number are same ` ` ` `if` `(lower ` `=` `=` `higher): ` ` ` `return` `lower ` ` ` `else` `: ` ` ` `return` `2` ` ` `# Driver Code ` `lower ` `=` `10` `# Lower number ` `higher ` `=` `20` `# Higher number ` ` ` `print` `(` `"The most frequent factor"` `, ` ` ` `mostCommon(lower, higher)) ` ` ` `# This code is contributed by ash264 ` |

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## C#

`// C# program to find most common factor ` `// in a range. ` `using` `System; ` ` ` `class` `GFG ` `{ ` `static` `int` `mostCommon(` `int` `lower, ` `int` `higher) ` `{ ` ` ` `// Check whether lower number ` ` ` `// and higher number are same ` ` ` `if` `(lower == higher) ` ` ` `return` `lower; ` ` ` `else` ` ` `return` `2; ` `} ` ` ` `// Driver Code ` `public` `static` `void` `Main() ` `{ ` ` ` `int` `lower = 10; ` `// Lower number ` ` ` `int` `higher = 20; ` `// Higher number ` ` ` ` ` `Console.WriteLine(` `"The most frequent factor "` `+ ` ` ` `mostCommon(lower, higher)); ` `} ` `} ` ` ` `// This code is contributed ` `// by Akanksha Rai ` |

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## PHP

`<?php ` `// PHP program to find most common ` `// factor in a range. ` ` ` `function` `mostCommon(` `$lower` `, ` `$higher` `) ` `{ ` ` ` `// Check whether lower number ` ` ` `// and higher number are same ` ` ` `if` `(` `$lower` `== ` `$higher` `) ` ` ` `return` `$lower` `; ` ` ` `else` ` ` `return` `2; ` `} ` ` ` `// Driver Code ` `$lower` `= 10; ` `// Lower number ` `$higher` `= 20; ` `// Higher number ` ` ` `echo` `"The most frequent factor "` `. ` ` ` `mostCommon(` `$lower` `, ` `$higher` `) . ` `"\n"` `; ` ` ` `// This code is contributed ` `// by Akanksha Rai ` `?> ` |

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**Output:**

The most frequent factor 2

**Time Complexity: **O(1)

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