Java signum() method with Examples
Last Updated :
09 Apr, 2018
The java.lang.Math.signum() returns the Sign function of a value passed to it as argument. The signum() function returns the following values depending on the argument passed to it:
- If the argument passed is greater than zero, then the signum() function will return 1.0.
- If the argument passed is equal to zero, then the signum() function will return 0.
- If the argument passed is less than zero, then the signum() function will return -1.0.
Note: If the argument passed is NaN, then the result is NaN. If the argument passed is positive zero or negative zero then the result will be same as that of the argument.
Syntax:
public static double signum(double d)
Parameter :
a : the value whose signum function is to be returned.
Return :
This method returns the signum function value of
the argument passed to it.
Example 1 : To show working of java.lang.Math.signum() method.
import java.lang.Math;
class Gfg {
public static void main(String args[])
{
double a = 30 ;
System.out.println(Math.signum(a));
a = 0 ;
System.out.println(Math.signum(a));
a = - 30 ;
System.out.println(Math.signum(a));
}
}
|
Output:
1.0
0
-1.0
Example 2 : To show working of java.lang.Math.signum() method when argument is NaN.
import java.lang.Math;
public class GFG {
public static void main(String[] args)
{
double nan = Double.NaN;
double result;
result = Math.signum(nan);
System.out.println(result);
result = Math.signum( 0 );
System.out.println(result);
result = Math.signum(- 0 );
System.out.println(result);
}
}
|
Output:
NaN
0.0
0.0
Share your thoughts in the comments
Please Login to comment...