# Java Program to check Armstrong Number

Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if.

```abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....
```

Example:

```Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153

Input : 120
Output : No
120 is not a Armstrong number.
1*1*1 + 2*2*2 + 0*0*0 = 9

Input : 1253
Output : No
1253 is not a Armstrong Number
1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723

Input : 1634
Output : Yes
1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634
```

## Java

 `// Java program to determine whether the number is ` `// Armstrong number or not ` `public` `class` `Armstrong ` `{ ` `    ``/* Function to calculate x raised to the ` `       ``power y */` `    ``int` `power(``int` `x, ``long` `y) ` `    ``{ ` `        ``if``( y == ``0``) ` `            ``return` `1``; ` `        ``if` `(y%``2` `== ``0``) ` `            ``return` `power(x, y/``2``)*power(x, y/``2``); ` `        ``return` `x*power(x, y/``2``)*power(x, y/``2``); ` `    ``} ` ` `  `    ``/* Function to calculate order of the number */` `    ``int` `order(``int` `x) ` `    ``{ ` `        ``int` `n = ``0``; ` `        ``while` `(x != ``0``) ` `        ``{ ` `            ``n++; ` `            ``x = x/``10``; ` `        ``} ` `        ``return` `n; ` `    ``} ` ` `  `    ``// Function to check whether the given number is ` `    ``// Armstrong number or not ` `    ``boolean` `isArmstrong (``int` `x) ` `    ``{ ` `        ``// Calling order function ` `        ``int` `n = order(x); ` `        ``int` `temp=x, sum=``0``; ` `        ``while` `(temp!=``0``) ` `        ``{ ` `            ``int` `r = temp%``10``; ` `            ``sum = sum + power(r,n); ` `            ``temp = temp/``10``; ` `        ``} ` ` `  `        ``// If satisfies Armstrong condition ` `        ``return` `(sum == x); ` `    ``} ` ` `  `    ``// Driver Program ` `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``Armstrong ob = ``new` `Armstrong(); ` `        ``int` `x = ``153``; ` `        ``System.out.println(ob.isArmstrong(x)); ` `        ``x = ``1253``; ` `        ``System.out.println(ob.isArmstrong(x)); ` `    ``} ` `} `

Please refer complete article on Program for Armstrong Numbers for more details!

My Personal Notes arrow_drop_up
Article Tags :

2

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.