Related Articles

# How to delete a range of values from the List using Iterator

• Last Updated : 18 Jan, 2019

Given a List, the task is to delete a range of values from this List using Iterator.

Example:

```Input: list = [10 20 30 40 50 60 70 80 90],
start_iterator = 3,
end_iterator = 8
Output: 10 20 80 90

Input: list = [1 2 3 4 5]
start_iterator = 1,
end_iterator = 3
Output: 3 4 5
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: In this method, a range of elements are deleted from the list. This is done with the help of two iterators. The first iterator points at the starting element of the range and the second iterator points at the last element of the range. The first iterator is exclusive while the last iterator is inclusive which means that element will also get deleted which is pointed by the last iterator.

Syntax:

```iterator erase (const_iterator startPositionIterator_exclusive,
const_iterator endingPositionIterator_inclusive);
```

Below is the implementation of the above approach:

Program:

 `// C++ program to delete an element``// of a List by passing its value`` ` `#include ``#include ``using` `namespace` `std;`` ` `// Function to print the list``void` `printList(list<``int``> mylist)``{``    ``// Get the iterator``    ``list<``int``>::iterator it;`` ` `    ``// printing all the elements of the list``    ``for` `(it = mylist.begin(); it != mylist.end(); ++it)``        ``cout << ``' '` `<< *it;``    ``cout << ``'\n'``;``}`` ` `// Function to delete the element of list``void` `deleteRange(list<``int``> mylist)``{``    ``// Printing all the elements of the list``    ``cout << ``"\nList originally: "``;``    ``printList(mylist);`` ` `    ``// Get the starting Iterator at 3rd element``    ``list<``int``>::iterator start_itr = mylist.begin();``    ``start_itr++;``    ``start_itr++;`` ` `    ``// Get the ending Iterator at 2nd last element``    ``list<``int``>::iterator end_itr = mylist.end();``    ``end_itr--;``    ``end_itr--;`` ` `    ``// Erase the elements in the range``    ``// of the iterators passed as the parameter``    ``mylist.erase(start_itr, end_itr);`` ` `    ``// Printing all the elements of the list``    ``cout << ``"List after deletion of range"``         ``<< ``" from 3rd till 2nd last: "``;``    ``printList(mylist);``}`` ` `// Driver Code``int` `main()``{``    ``list<``int``> mylist;`` ` `    ``// Get the list``    ``for` `(``int` `i = 1; i < 10; i++)``        ``mylist.push_back(i * 10);`` ` `    ``// Delete an element from the List``    ``deleteRange(mylist);`` ` `    ``return` `0;``}`
Output:
```List originally:  10 20 30 40 50 60 70 80 90
List after deletion of range from 3rd till 2nd last:  10 20 80 90
```
Want to learn from the best curated videos and practice problems, check out the C++ Foundation Course for Basic to Advanced C++ and C++ STL Course for foundation plus STL.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

My Personal Notes arrow_drop_up