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How to add one polynomial to another using NumPy in Python?
• Last Updated : 29 Aug, 2020

In this article, Let’s see how to add one polynomial to another. Two polynomials are given as input and the result is the addition of two polynomials.

• The polynomial p(x) = C3 x2 + C2 x + C1  is represented in NumPy as : ( C1, C2, C3 ) { the coefficients (constants)}.
• Let take two polynomials p(x) and q(x) then add these to get r(x) = p(x) + q(x) as a result of addition of two input polynomials.
```If p(x) = A3 x2 + A2 x + A1
and
q(x) = B3 x2 + B2 x + B1

then result is
r(x) = p(x) + q(x)
i.e;
r(x) = (A3 + B3) x2 + (A2 + B2) x + (A1 + B1)

and output is
( (A1 + B1), (A2 + B2), (A3 + B3) )
```

Below is the implementation with some examples :

Example 1: simple_use

## Python3

 `# importing package``import` `numpy`` ` `# define the polynomials``# p(x) = 5(x**2) + (-2)x +5``px ``=` `(``5``,``-``2``,``5``)`` ` `# q(x) = 2(x**2) + (-5)x +2``qx ``=` `(``2``,``-``5``,``2``)`` ` `# add the polynomials``rx ``=` `numpy.polynomial.polynomial.polyadd(px,qx)`` ` `# print the resultant polynomial``print``(rx)`

Output :

```[ 7. -7.  7.]
```

Example 2: #add_with_decimals

## Python3

 `# importing package``import` `numpy`` ` `# define the polynomials``# p(x) = 2.2``px ``=` `(``0``,``0``,``2.2``)`` ` `# q(x) = 9.8(x**2) + 4``qx ``=` `(``9.8``,``0``,``4``)`` ` `# add the polynomials``rx ``=` `numpy.polynomial.polynomial.polyadd(px,qx)`` ` `# print the resultant polynomial``print``(rx)`

Output :

```[ 9.8  0.   6.2]
```

Example 3: eval_then_add

## Python3

 `# importing package``import` `numpy`` ` `# define the polynomials``# p(x) = (5/3)x``px ``=` `(``0``,``5``/``3``,``0``)`` ` `# q(x) = (-7/4)(x**2) + (9/5)``qx ``=` `(``-``7``/``4``,``0``,``9``/``5``)`` ` `# add the polynomials``rx ``=` `numpy.polynomial.polynomial.polyadd(px,qx)`` ` `# print the resultant polynomial``print``(rx)`

Output :

```[-1.75        1.66666667  1.8       ]
```

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