HijrahDate isLeapYear() method in Java with Example
Last Updated :
27 Feb, 2020
The isLeapYear() method of java.time.chrono.HijrahDate class is used to differentiate between the leap year and non leap year. If the year represented by this HijrahDate is a leap year, this method will return true, otherwise false.
Syntax:
public boolean isLeapYear()
Parameter: This method does not accept any argument as a parameter.
Return Value: This method returns Boolean value, i.e. true if the proleptic year is leap year otherwise false.
Below are the examples to illustrate the isLeapYear() method:
Example 1:
Java
import java.util.*;
import java.io.*;
import java.time.*;
import java.time.chrono.*;
public class GFG {
public static void main(String[] argv)
{
HijrahDate hidate
= HijrahDate.of( 1398 , 03 , 23 );
System.out.println( "HijrahDate: "
+ hidate.toString());
boolean flag = hidate.isLeapYear();
if (flag)
System.out.println( "Leap year" );
else
System.out.println( "Not a leap year" );
}
}
|
Output:
HijrahDate: Hijrah-umalqura AH 1398-03-23
Not a leap year
Example 2:
Java
import java.util.*;
import java.io.*;
import java.time.*;
import java.time.chrono.*;
public class GFG {
public static void main(String[] argv)
{
HijrahDate hidate = HijrahDate.now();
System.out.println( "HijrahDate: "
+ hidate.toString());
boolean flag = hidate.isLeapYear();
if (flag)
System.out.println( "Leap year" );
else
System.out.println( "Not a leap year" );
}
}
|
Output:
HijrahDate: Hijrah-umalqura AH 1441-06-25
Leap year
Reference: https://docs.oracle.com/javase/9/docs/api/java/time/chrono/HijrahDate.html#isLeapYear–
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