Golang Program to Show the Duplicate Case Error in Switch Statement
A switch’s case must have a unique value. When repeated value is checked against the entire switch. The “duplicate case” error is arised. Let us discuss duplicate case error with the help of the examples:
Example 1:
Go
// Golang program that causes // duplicate case error package main import "fmt" // Main function func main() { value := 4 // Duplicate cases are not allowed. switch value { case 4: fmt.Println(true) case 4: fmt.Println(true) } } |
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Output:
./prog.go:15:10: duplicate case 4 in switch
previous case at ./prog.go:13:10
Example 2:
Go
// Golang program that causes // duplicate case error package main import "fmt" // Main function func main() { i := 1 switch i { case 0, 1: fmt.Println("GeeksForGeeks") fallthrough case 0: fmt.Println("Geeks_0") case 1: fmt.Println("Geeks_1") default: fmt.Println("Number_of_Users") } } |
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Output:
./prog.go:15:8: duplicate case 0 in switch
previous case at ./prog.go:12:8
./prog.go:17:8: duplicate case 1 in switch
previous case at ./prog.go:12:11
