Golang Program to Show the Duplicate Case Error in Switch Statement

A switch’s case must have a unique value. When repeated value is checked against the entire switch. The “duplicate case” error is arised. Let us discuss duplicate case error with the help of the examples:

Example 1:

Go

// Golang program that causes  
// duplicate case error 
   
package main 
  
import "fmt"
  
// Main function 
func main() { 
    value := 4
  
    // Duplicate cases are not allowed. 
    switch value { 
    case 4: 
        fmt.Println(true) 
    case 4: 
        fmt.Println(true) 
    } 
} 

Output:

./prog.go:15:10: duplicate case 4 in switch
    previous case at ./prog.go:13:10

Example 2:

Go

// Golang program that causes  
// duplicate case error 
   
package main 
  
import "fmt"
  
// Main function 
func main() { 
    i := 1
    switch i { 
        case 0, 1: 
            fmt.Println("GeeksForGeeks") 
            fallthrough
        case 0: 
            fmt.Println("Geeks_0") 
        case 1: 
            fmt.Println("Geeks_1") 
        default: 
            fmt.Println("Number_of_Users") 
    } 
} 

Output:

./prog.go:15:8: duplicate case 0 in switch
    previous case at ./prog.go:12:8
./prog.go:17:8: duplicate case 1 in switch
    previous case at ./prog.go:12:11

My Personal Notes

Recommended Posts:

SHUBHAMSINGH10

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Improved By : Akanksha_Rai