In the figure below, ∠DEC+∠BFC is equal to _______ .
(A) ∠ BCD – ∠ BAD
(B) ∠ BAD + ∠ BCF
(C) ∠ BAD + ∠ BCD
(D) ∠ CBA + ∠ ADC
Explanation: Option (A) is correct.
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