In the figure below, ∠DEC+∠BFC is equal to _______ .
(A) ∠BCD – ∠BAD
(B) ∠BAD + ∠BCF
(C) ∠BAD + ∠BCD
(D) ∠CBA + ∠ADC
Answer: (A)
Explanation: Option (A) is correct.
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