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GATE | GATE-CS-2016 (Set 1) | Question 16

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Consider the Boolean operator # with the following properties: x#0 = x, x#1 = x’, x#x = 0 and x#x’ = 1 Then x#y is equivalent to (A) x’y + xy’ (B) xy’ + (xy) (C) x’y + xy (D) xy + (xy)’

Answer: (A)

Explanation: The function # basically represents XOR. Following are true with XOR. 1) XOR of x with 0 is x itself. 2) XOR of x with 1 is complement of x. 3) XOR of x with x is 0. 4) XOR of x with x’ is 1. XOR is represented as x’y + y’x.

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Last Updated : 20 Sep, 2021
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